Mean: add all of the values together and then divide by the number of values
mean= 47.857
Median: like up the numbers least to greatest and then find the number in the middle. if there is an even number of values, take the average of the two middle values
median= 45
The mean reflects the beet measure of the center.
Using probability concepts, it is found that:
a) 
probability of drawing a card below a 6.
b) 
odds of drawing a card below a 6.
c) We should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
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- A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.
Item a:
- In a standard deck, there are 52 cards.
- There are 4 types of cards, each numbered 1 to 13. Thus,
are less than 6.
Then:
probability of drawing a card below a 6.
Item b:
- Converting from probability to odd, it is:
odds of drawing a card below a 6.
Item c:
- The law of large numbers states that with a <u>large number of trials, the percentage of each outcome is close to it's theoretical probability.</u>
- Thus, we should expect to draw a card below 6 about 4 times out of 13 attempts, which as an odd, it also 4 times for every 9 times we draw a card above 6, which is the third option.
A similar problem is given at brainly.com/question/24233657
Answer:
<h2>interest on saving accounts</h2><h2 />
Step-by-step explanation:
Answer:
No it isnt possible
Step-by-step explanation:
it is not because 2,783,000 is not divisible by 9
Answer:
Step-by-step explanation:
Both 115 and 145 mph are above the mean. Draw a normal curve and mark these speeds. 115 mph is 1 standard deviation above the mean; 130 would be 2 standard deviations above the mean; and 145 would be 3 s. d. above it.
We need to find the area under the standard normal curve between 115 and 145. This is equivalent to the area under the standard normal curve between z = 1 and z = 3.
I used my TI-83 Plus calculator's DISTR function "normalcdf(" to calculate this area: normalcdf(1, 3) = 0.1573.
The area between z = 1 and z = 3 is 0.1573. In other words, the percentage of serves that were between 115 and 145 mph was 15.73%.
