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Sliva [168]
3 years ago
10

In ΔPQR, ∠P and ∠Q are complementary angles. If sin Q = 3/5, then what is cos P + cos q

Mathematics
1 answer:
antiseptic1488 [7]3 years ago
3 0

Answer:7/5

Step-by-step explanation:

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6 0
3 years ago
FIND (-8/3)+(-1/4)+(-11/6)+3/8-3
emmainna [20.7K]

Answer:

-7 3/8

Step-by-step explanation:

The least common denominator of 3, 4, 6, and 8 is 24; converting all of our fractions to that denominator and solving, we have

-\frac{8}{3}+\left(-\frac{1}{4}\right)+\left(-\frac{11}{6}\right)+\frac{3}{8}-3\\=-\frac{64}{24}+\left(-\frac{6}{24}\right)+\left(-\frac{44}{24}\right)+\frac{9}{24}-3\\\\=\frac{-64+(-6)+(-44)+9}{24} -3\\\\=\frac{-70+(-44)+9}{24} -3\\\\=\frac{-114+9}{24} -3\\\\=\frac{-105}{24}-3 \\\\=\frac{-35}{8}-3\\ \\=-4\frac{3}{8}-3\\\\=-7\frac{3}{8}

So our solution is -7 3/8

8 0
3 years ago
 if angle RZT=110, angle RZS=3s, and angle TZS=8s, what are angle RZS and angle TZS?
skelet666 [1.2K]
8s-3s=5s
5s=110
Divide both sides by 5 => s=22
RZS = 3s = 3(22) = 66
TZS= 8s = 8(22) = 176
7 0
3 years ago
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