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qaws [65]
3 years ago
9

Plug x= 2 into 2x^4 - 3x^2 +5

Mathematics
1 answer:
GaryK [48]3 years ago
8 0

Answer:

For example, try entering the equation 3x+2=14 into the text box. ... Here are some examples: y=2x^2+1, y=3x-1, x=5, x=y^2. To graph ... enter the expression you want to evaluate,  want to    

Step-by-step explanation:

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C Is the correct choice
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When all the kids who tried out for Little League
Akimi4 [234]

Answer:

160 players, I hope it helps

Step-by-step explanation:

5 0
3 years ago
For males in a certain town, the systolic blood pressure is normally distributed with a mean of 125 and a standard deviation of
makkiz [27]

95% have a systolic blood pressure between 109 and 141

Empirical rule states that for a normal distribution, 68% are within one standard deviation from the mean, 95% are within two standard deviation from the mean and 99.7% are within three standard deviation from the mean.

Given that mean (μ) = 125, standard deviation (σ) = 8.

68% are within one standard deviation = μ ± σ = 125 ± 8 = (117, 133)

95% are within two standard deviation = μ ± 2σ = 125 ± 2*8 = (109, 141)

95% have a systolic blood pressure between 109 and 141

Find out more on empirical rule at: brainly.com/question/10093236

5 0
3 years ago
Today only, a table is being sold for $459. This is 68% of its regular price. What was the price yesterday?
lianna [129]
$459+68%

68% of $459 is $312.12

$459+312.12=

$771.12

So the price of the table the day before should be $771.12
5 0
3 years ago
Read 2 more answers
What is the greatest integer a, such that a^2 + 3b is less than (2b)^2, assuming that b is 5? Please answer and have a nice day!
solniwko [45]
<h3>Answer: Largest value is a = 9</h3>

===================================================

Work Shown:

b = 5

(2b)^2 = (2*5)^2 = 100

So we want the expression a^2+3b to be less than (2b)^2 = 100

We need to solve a^2 + 3b < 100 which turns into

a^2 + 3b < 100

a^2 + 3(5) < 100

a^2 + 15 < 100

after substituting in b = 5.

------------------

Let's isolate 'a'

a^2 + 15 < 100

a^2 < 100-15

a^2 < 85

a < sqrt(85)

a < 9.2195

'a' is an integer, so we round down to the nearest whole number to get a \le 9

So the greatest integer possible for 'a' is a = 9.

------------------

Check:

plug in a = 9 and b = 5

a^2 + 3b < 100

9^2 + 3(5) < 100

81 + 15 < 100

96 < 100 .... true statement

now try a = 10 and b = 5

a^2 + 3b < 100

10^2 + 3(5) < 100

100 + 15 < 100 ... you can probably already see the issue

115 < 100 ... this is false, so a = 10 doesn't work

5 0
3 years ago
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