Question

A 1kg box is pushed on a flat surface that is 250m long. The box is initially at rest and then pushed with a constant Net force of 5N along the entire length. What is the velocity of the box when it reaches the end of the surface.
A. 25m/s

B. 2500m/s

C. 50m/s

D. 75m/s

Answer 1

Answer:

C) 50 m/s

Explanation:

With the given information we can calculate the acceleration using the force and mass of the box.

Newton's 2nd Law: F = ma

• 5 N = 1 kg * a
• a = 5 m/s²

List out known variables:

• v₀ = 0 m/s
• a = 5 m/s²
• v = ?
• Δx = 250 m

Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:

• v² = v₀² + 2aΔx

Substitute known values into the equation and solve for v.

• v² = (0)² + 2(5)(250)
• v² = 2500
• v = 50 m/s

The final velocity of the box is C) 50 m/s.