Question

A person in a kayak starts paddling, and it accelerates from 0 to 0.680 m/s in a distance of 0.428 m. If the combined mass of the person and the kayak is 82.7 kg, what is the magnitude of the net force acting on the kayak?

Answer 1

Answer:

Net force, F = 44.66 N

Explanation:

It is given by,

Initial velocity of the person, u = 0

Final velocity of the person, v = 0.68 m/s

Distance, s = 0.428 m

Combined mass of the person and the kayak, m = 82.7 kg

We need to find the net force acting on the kayak i.e.

F = ma...........(1)

Firstly, we will calculate the value of "a" from third equation of motion as :

$v^2-u^2=2as$

$a=\dfrac{v^2-u^2}{2s}$

$a=\dfrac{(0.68\ m/s)^2-0}{2\times 0.428\ m}$

$a=0.54\ m/s^2$

Put the value of a in equation (1) as :

$F=82.7\ kg\times 0.54\ m/s^2$

F = 44.66 N

So, the net force acting on the kayak is 44.66 N. Hence, this is the required solution.