A 30.0-kg girl in a swing is pushed to one side and held at rest by a horizontal force \vec{F} F ⃗ so that the swing ropes
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Answer:
(a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.
Explanation:
Given that,
Speed = 33 m/s
Angle = 60°
Time = 3.0 sec
(a). We need to calculate the height of the cliff
Using equation of motion
Put the value into the formula
(b). We need to calculate the maximum height of the ball
Using formula of height
Put the value into the formula
(c). We need to calculate the vertical component of velocity of ball
Using equation of motion
Put the value into the formula
We need to calculate the horizontal component of velocity of ball
Using formula of velocity
Put the value into the formula
We need to calculate the ball's impact speed
Using formula of velocity
Put the value into the formula
Hence, (a). The height of the cliff is 41.67 m.
(b). The maximum height of the ball is 41.67 m
(c). The ball's impact speed is 16.52 m/s.