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3 years ago

A baseball player runs 27 m from third base to home plate in 3.2 s. What is

Physics

2 answers:

mars1129 [50]3 years ago

5 0

Answer:

8.44 m/s

Explanation:

Averag v = distance/time

= 27m/3.2s

= 8.44 m/secs

romanna [79]3 years ago

4 0

Answer:

8.4375m a second

Explanation:

Again, this is such an easy question that I see everywhere. The way to figure this out is to divided the total distance he or she covered, which was 27m, by the time it took him or her to do so, which was 3.2s, so the equation is 27 divded by 3.2 which is 8.4375.

Hope this helps and have a great day.

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A 0.272-kg volleyball approaches a player horizontally with a speed of 12.6 m/s. The player strikes the ball with her fist and c

Nady [450]

(a) +9.30 kg m/s

The impulse exerted on an object is equal to its change in momentum:

$I= \Delta p = m \Delta v = m (v-u)$

where

m is the mass of the object

$\Delta v$ is the change in velocity of the object, with

v = final velocity

u = initial velocity

For the volleyball in this problem:

m = 0.272 kg

u = -12.6 m/s

v = +21.6 m/s

So the impulse is

$I=(0.272 kg)(21.6 m/s - (-12.6 m/s)=+9.30 kg m/s$

(b) 155 N

The impulse can also be rewritten as

$I=F \Delta t$

where

F is the force exerted on the volleyball (which is equal and opposite to the force exerted by the volleyball on the fist of the player, according to Newton's third law)

$\Delta t$ is the duration of the collision