If a substance or object has the ability to do work, then it has

If there is 3.4 m3 of methane gas in a container with a pressure of 18.9 atm and the container expands until the methane has a p

Veseljchak [2.6K]

Answer:

C. 29.21 m³

Explanation:

<u>Given the following data;</u>

Initial volume, V1 = 3.4 m³
Initial pressure, P1 = 18.9 atm
Final pressure, P2 = 2.2 atm

To find the final volume, we would use Boyle's law;

Boyles states that when the temperature of an ideal gas is kept constant, the pressure of the gas is inversely proportional to the volume occupied by the gas.

Mathematically, Boyles law is given by;

PV = K

$P_{1}V_{1} = P_{2}V_{2}$

Making V2 the subject of formula, we have;

$V_{2} = \frac {P_{1}V_{1}}{P_{2}}$

Substituting the values into the formula, we have;

$V_{2} = \frac {18.9 * 3.4}{2.2}$

$V_{2} = \frac {64.26}{2.2}$

<em>Final volume, V2 = 29.21 m³</em>

7 0

3 years ago

Many cultures around the world still use a simple weapon called a blowgun, a tube with a dart that fits tightly inside. A sharp

Yuki888 [10]

Answer:

F = 1.06N

Explanation:

In order to calculate the force that produces the given pressure you take into account the following formula:

$P=\frac{F}{A}$ (1)

P: pressure = 6.0kPa = 6.0*10³ Pa

F: force = ?

A: cross-sectional area of the tube = π r^2

r: radius of the tube = 1.5cm/2 = 0.75cm = 0.75*10^-2 m

You solve the equation (1) for F, and replace the values for the area A and the pressure P:

$F=PA=(6.0*10^{3}Pa)(\pi(0.75*10^{-2}m)^2)\\\\F=1.06N$

The force tha produces a pressure of 6.0kPa in a tube with a diameters of 1.5cm is 1.06N

7 0

3 years ago

Why must you balance an equation to describe correctly what happens in a chemical reaction

wariber [46]

Where you get all the steps when you finally get a reaction . Ex, vinegar and baking soda you go step by step.

Hope this helps :)

5 0

3 years ago

Your neighbor Paul has rented a truck with a loading ramp. The ramp is tilted upward at 25°, and Paul is pulling a large crate u

Alisiya [41]

Explanation:

It is given that,

The ramp is tilted upwards at 25 degrees and Paul is pulling a large crate up the ramp with a rope that angles 10° above the ramp.

Total angle with respect to ramp is 35 degrees.

If Paul pulls with a force of 550 N.

The horizontal component of the force is given by :

$F_x=F\ cos\theta$

$F_x=550\ cos(35)$

$F_x=450.53\ N$

The vertical component of the force is given by :

$F_y=F\ sin\theta$

$F_y=550\ sin(35)$

$F_y=315.46\ N$

Hence, this is the required solution.

4 0

3 years ago

A sample of a gas has a volume of 639 cm3 when the pressure is 75.9 kPa. What is the volume of the gas when the pressure is incr

const2013 [10]

Answer:

$388 cm^3$

Explanation:

For this problem, we can use Boyle's law, which states that for a gas at constant temperature, the product between pressure and volume remains constant:

$pV=const.$