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Ghella [55]
3 years ago
12

A software team is setting an automation strategy and begins by identifying business processes that could benefit from automatio

n. What should be the team's next step after this?
Computers and Technology
1 answer:
hoa [83]3 years ago
5 0

Answer:

Defining the processes in clear unambiguous language

Explanation:

An example of a automation development process is the development of a program which is similar to a problem solving process

The first step after identification of the processes that could benefit from automation includes;

Defining each process, clearly and unambiguously including;

The input and output of the process

The process resources

The process location and operation

The process objectives and deliverables

How the process is used

The common difficulties using the current process

The common tasks of the process

The process efficiencies

The adaptability of the process

With the above process definition, the team can proceed to the planning stages, including;

Proposals of the intended automation to be implemented in the system

The additional resources that would be required for the automation

The automation design

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A. An Even Number is the answer!
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What should you do to help prepare yourself for the delivery of your presentation? you can chose more then one
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Hope this helps!
4 0
3 years ago
The words, the computer is the future, has how many bits?
Nadusha1986 [10]

The words, the computer is the future, has 64 bits.Modern computer has

two types of processors which include:

  • 32 bit
  • 64 bit
<h3>Bits</h3>

This is referred to as the smallest unit of data which is used in a computer.

The 32 bit computer are the old types which have a smaller processor and is

relatively slow.

The 64 bit computer on the other hand are the modern types with large

processors and are relatively fast.

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4 0
2 years ago
First, launch NetBeans and close any previous projects that may be open (at the top menu go to File ==&gt; Close All Projects).
Mars2501 [29]

Answer:

See explaination

Explanation:

// LetterCount.java

import java.io.File;

import java.io.IOException;

import java.io.PrintWriter;

import java.util.NoSuchElementException;

import java.util.Scanner;

public class LetterCount {

public static void main(String[] args) {

// setting up a Scanner to read from keyboard

Scanner scanner = new Scanner(System.in);

try {

// asking and reading input file name

System.out.print("Enter name of input file: ");

String file = scanner.nextLine();

// reinitializing scanner to read from input file. this will throw

// file not found exception if file is not found.

scanner = new Scanner(new File(file));

// opening a file writer to create and write into output.txt file

PrintWriter writer = new PrintWriter(new File("output.txt"));

// creating a String containing all 26 alphabets

String alphabet = "abcdefghijklmnopqrstuvwxyz";

// creating an array containing 26 integers, all initialized to 0

int counts[] = new int[26];

// looping through the file

while (scanner.hasNext()) {

// reading next line, converting to lower case

String word = scanner.next().toLowerCase();

// looping through each character in current word

for (char c : word.toCharArray()) {

// finding index of c in alphabet

int index = alphabet.indexOf(c);

// if c is an alphabet, the index value will not be -1

if (index != -1) {

// incrementing counter at index position

counts[index]++;

}

}

}

// closing input file

scanner.close();

int largestCount = 0; // to store largest count of a character

String mostCommon = ""; // to store the character(s) that occur the

// most

// looping through counts array, finding the largest value

for (int i = 0; i < counts.length; i++) {

if (counts[i] > largestCount) {

// updating largestCount and mostCommon

largestCount = counts[i];

mostCommon = alphabet.charAt(i) + "";

} else if (counts[i] == largestCount) {

// same largest count, appending to mostCommon string

mostCommon += " " + alphabet.charAt(i);

}

}

// writing results to output file

writer.println("The most common letter(s): " + mostCommon);

writer.println("Count of occurrances: " + largestCount);

// closing file, saving changes, alerting user

writer.close();

System.out

.println("done! please check output.txt file for results.");

} catch (IOException e) {

// will be executed when the input/output file cant be opened or

// found, or if there is an error while reading the file

System.out.println(e.getMessage());

} catch (NoSuchElementException e) {

// will occur when there is no input provided for input file name.

System.out.println("No input!");

}

}

}

8 0
3 years ago
Construct a class that will model a quadratic expression (ax^2 + bx + c). In addition to a constructor creating a quadratic expr
stich3 [128]

Answer:

Following are the code to this question:

#include <iostream>//header file

#include<math.h>//header file

using namespace std;

class Quadratic//defining a class Quadratic  

{

private:

double a,b,c;//defining a double variable

public:

Quadratic()//defining default constructor

{

a = 0;//assigning value 0  

b = 0;//assigning value 0  

c = 0;//assigning value 0  

}

Quadratic(double a, double b, double c)//defining a parameterized constructor  

{

this->a = a;//use this keyword to hold value in a variable

this->b = b;//use this keyword to hold value in b variable

this->c = c;//use this keyword to hold value in c variable

}

double getA() //defining a get method  

{

return a;//return value a

}

void setA(double a)//defining a set method to hold value in parameter

{

this->a = a;//assigning value in a variable

}

double getB() //defining a get method  

{

return b;//return value b

}

void setB(double b)//defining a set method to hold value in parameter  

{

this->b = b;//assigning value in b variable

}

double getC() //defining a get method

{

return c;//return value c

}

void setC(double c)//defining a set method to hold value in parameter

{

this->c = c;//assigning value in c variable

}

double Evaluate(double x)//defining a method Evaluate to hold value in parameter

{

return ((a*x*x)+(b*x)+c);//return evaluated value

}

double numberOfReal()//defining a method numberOfReal to calculates the real roots

{

return (b*b)-(4*a*c);//return real roots

}

void findroots()//defining a method findroots

{

double d=numberOfReal();//defining double variable to hold numberOfReal method value

if(d<0)//use if block to check value of d less than 0

cout<<"Equation has no real roots"<<endl;//print message

else

{

double r1=(-b+sqrt(numberOfReal()))/(2*a);//holding root value r1

double r2=(-b-sqrt(numberOfReal()))/(2*a);//holding root value r2

if(r1==r2)//defining if block to check r1 equal to r2

cout<<"Equation has one real root that is "<<r1<<endl;//print message with value

else//else block

cout<<"The equation has two real roots that are "<<r1<<" and "<<r2<<endl;////print message with value

}

}

void print()//defining a method print  

{

cout<< a << "x^2 + " << b << "x + " << c <<endl;//print Quadratic equation

}

};

int main()//defining main method  

{

Quadratic q(5,6,1);//creating Quadratic class object that calls parameterized constructor

q.print();//calling print method

cout<<q.numberOfReal()<<endl;//calling method numberOfReal that prints its value

q.findroots();//calling method findroots

cout<<q.Evaluate(-1);//calling method Evaluate that prints its value

return 0;

}

Output:

5x^2 + 6x + 1

16

The equation has two real roots that are -0.2 and -1

0

Explanation:

In the above code, a class "Quadratic" is declared, which is used to define a default and parameter constructor to holds its parameter value.

In the next step, the get and set method is defined that holds and returns the quadratic value, and "Evaluate, numberOfReal, findroots, and print" in the evaluate method a double variable is used as a parameter that returns evaluated value.

In the "numberOfReal" method it calculates the real roots and returns its value. In the "findroots" method a double variable "d" is declared that hold "numberOfReal" value,

and use a conditional statement to check its value, and in the print method, it prints the quadratic equation.

In the main method, the lass object it calls the parameterized constructor and other methods.

5 0
3 years ago
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