Answer:
23.27 L
Explanation:
The balanced reaction of ammonia and nitrogen monoxide is shown below as:
4NH₃(g) + 6NO(g) ⇒ 5N₂(g) + 6H₂O(l)
Given that:
Volume of nitrogen monoxide = 34.9 L
Since, temperature and pressure are same, volume coefficients would be same as equation coefficients.
So,
6 L of nitrogen monoxide reacts with 4 L of ammonia.
1 L of nitrogen monoxide reacts with 4/6 L of ammonia.
34.9 L of nitrogen monoxide reacts with (4/6)*34.9 L of ammonia.
Amount of ammonia required = 23.27 L
Okay so i think the answer to this is.
weight=mg
m=0.000100 g=9.80
so weight= 0.00980 kgm/s2
Hopefully thats correct (i am horrible at math)
Lassa fever is extremely dangerous (please note researchers have a rough time correctly determing how dangerous a virus is because many have not had a major outbreak and a vrius will react differently to everyones body.)
The answer is 79.9 g.
Copper takes 92.0% of aluminum bronze and it is a limiting factor. We have aluminum in excess, so we need to make a proportion.
If 73.5 g of copper are 92.0%, how many g of aluminum bronze will be 100%:
73.5 g : 92.0% = x : 100%.
x = 73.5 g : 100% * 92.0%
x = 79.9 g
Therefore, from 73.5 g of copper and 6.4 g of aluminum (since 79.9 g - 73.5 g = 6.4 g), maximum 79.9 g of aluminum bronze can be prepared.
Answer:
See below.
Explanation:
They both have 1 valency electron so will be metallic and in the same Group (Group 1) of the Periodic Table, so will have similar properties.
