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n200080 [17]
3 years ago
10

Question 2 (0 points)

Chemistry
1 answer:
bazaltina [42]3 years ago
5 0

Answer:

The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

Explanation:

Given that,

Total color in spinner = 4

Let the area of four parts is equal in the spinner.

We need to calculate the probability of spinning red

Using formula of probability

P(A) = \dfrac{Number\ of\ red\ color\ outcome}{Total\ number\ of\ colors\ in\ the\ spinner}

Put the value into the formula

P(A)=\dfrac{1}{4}

We need to calculate the probability of odd number of the die

Using formula of probability

P(B) = \dfrac{Number\ of\ odd\ digits\ outcome}{Total\ number\ of\ digits\ in\ the\ die}

Put the value into the formula

P(B)=\dfrac{3}{6}

P(B)=\dfrac{1}{2}

We need to calculate the probability  of spinning red with the spinner or rolling an odd number with the  die

Using formula of probability of two events which is independent

P(A\ and\ B)=P(A)\times P(B)

Put the value into the formula

P(A\ and\ B)=\dfrac{1}{4}\times\dfrac{1}{2}

P(A\ and\ B)=\dfrac{1}{8}

Hence, The probability  of spinning red with the spinner or rolling an odd number with the  die is \dfrac{1}{8}

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When blood is donated, sodium oxalate solution is used to precipitate Ca2+, which triggers clotting. A 122.0−mL sample of blood
icang [17]

Answer:

[Ca2+] = 3.36 * 10^-8 M

Explanation:

Step 1: Data given

A 122.0−mL sample of blood contains 9.70 * 10^−5 g Ca2+/mL.

A technologist treats the sample with 100.0 mL of 0.1550 M Na2C2O4.

Ksp = 2.30 * 10^−9

Step 2: Calculate mass of Ca2+

Mass Ca2+ = 9.70 * 10^−5 g Ca2+/mL * 122 mL

Mass Ca2+ = 0.011834 grams

Step 3: Calculate moles of Ca2+

Moles Ca2+ = mass Ca2+ / molar mass Ca2+

Moles Ca2+ = 0.011834 grams / 40.078 g/mol

Moles Ca2+ = 2.95 *10^-4 moles = 0.000295

Step 4: Calculate moles of C2O4^2-

Moles C2O4^2- = Molarity * volume

Moles C2O4^2- = 0.1550 M * 0.100 L

Moles C2O4^2- = 0.0155 moles

Step 5: Calculate limiting reactant

Ca2+ is the limiting reactant. It will completely be consumed ( 0.000295 moles).

C2O4^2- is in excess. There will 0.000295 moles be consumed. There will remain 0.0155 - 0.000295 = 0.015205 moles of C2O4^2-

Step 6: Calculate total volume

Total volume = 122.0 mL + 100.0 mL = 222.0 mL = 0.222 L

Step 7: Calculate concentration CaC2O4

[CaC2O4] = 0.000295 mol / 0.222 L

[CaC2O4] = 0.00133 M

Step 8: Calculate concentration of C2O4^2-

[C2O4^2-] = 0.015205 mol / 0.222L

[C2O4^2-] = 0.0685 M

Step 9: Calculate [Ca2+]

Ksp = 2.3 * 10^-9 = [Ca2+] [C2O42-]

2.3 * 10^-9 = X * (X+0.0685)

X = [Ca2+] = 3.36 * 10^-8 M

6 0
3 years ago
If you had 10.00 mL of acetic acid that you titrated with .100 M NaOH, and you used 45.15 mL of that base to get a light pink co
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Answer:

0.4515 M

Explanation:

In case of titration , the following formula can be used -

M₁V₁ = M₂V₂

where ,

M₁ = concentration of acid ,

V₁ = volume of acid ,

M₂ = concentration of base,

V₂ = volume of base .

from , the question ,

M₁ = ? M

V₁ = 10.0 mL

M₂ = 0.100 M

V₂ = 45.15 mL

Using the above formula , the molarity of acid , can be calculated as ,

M₁V₁ = M₂V₂

M₁ * 10.0mL = 0.100 M  * 45.15 mL  

M₁ = 0.4515 M

Hence, the concentration of the acetic acid = 0.4515 M

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true

Explanation:

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