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3 years ago

Convert Standard Form to Factored Form (SHOW ALL WORK) (LT 5.6) j(x)=x²+7X-18

Mathematics

1 answer:

loris [4]3 years ago

3 0

Answer:

j(x)=a(x+9)(x-2)

j(x)=1(x+9)(x-2) < final answer

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Evaluate the line integral, where c is the given curve. c y3 ds,

postnew [5]

Parameterizing $\mathcal C$ by

$\mathbf r(t)=(t^3,t)$

with $0\le t\le2$ , we have

$\mathrm ds=\|\mathbf r'(t)\|\,\mathrm dt=\sqrt{(3t^2)^2+1^2}\,\mathrm dt=\sqrt{9t^4+1}\,\mathrm dt$

So

$\displaystyle\int_{\mathcal C}y^3\,\mathrm ds=\int_{t=0}^{t=2}t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_0^236t^3\sqrt{9t^4+1}\,\mathrm dt$
$=\displaystyle\frac1{36}\int_{u=1}^{u=145}\sqrt u\,\mathrm du$
$=\dfrac{145^{3/2}-1}{54}$

5 0

4 years ago

The age of some lecturers are 42,54,50,54,50,42,46,46,48 and 48 calculate the mean age and standard deviation

rjkz [21]

Answer:

Mean age: 48

Standard deviation: 4

Step-by-step explanation:

a) Mean

The formula for Mean = Sum of terms/ Number of terms

Number of terms

= 42 + 54 + 50 + 54 + 50 + 42 + 46 + 46 + 48+ 48/ 10

= 480/10

= 48

The mean age is 48

b) Standard deviation

The formula for Standard deviation =

√(x - Mean)²/n

Where n = number of terms

Standard deviation =

√[(42 - 48)² + (54 - 48)² + (50 - 48)² +(54 - 48)² + (50 - 48)² +(42 - 48)² + (46 - 48)² + (46 - 48)² + (48 - 48)² + (48 - 48)² / 10]

= √-6² + 6² + 2² + 6² + 2² + -6² + -2² + -2² + 0² + 0²/10

=√36 + 36 + 4 + 36 + 4 + 36 + 4 + 4 + 0 + 0/ 10

=√160/10

= √16

= 4

The standard deviation of the ages is 4

3 0

4 years ago

URGENTTT! CAN SOMEONE PLEASE HELP?

miskamm [114]

Answer:

Hey there!

We have tangent 29=h/400

Thus, tangent 29 times 400=h

h=221.7 feet.

The height of the kite is 221.7 feet.

Hope this helps :)

8 0

4 years ago

PLEASE HELP WIL MARK BRAINLIEST MY DUDE

mihalych1998 [28]

Answer:

I think the answer is D

Step-by-step explanation:

5 0

3 years ago

Find a number that is between2/9and3/11

SVETLANKA909090 [29]

$\text {Between } \dfrac{2}{9} \text { and } \dfrac{3}{11}$

Change the denominators to be the same:
$\text {Between } \dfrac{2 \times 11}{9 \times 11} \text { and } \dfrac{3 \times 9}{11 \times 9}$

$\text {Between } \dfrac{22}{99} \text { and } \dfrac{27}{99}$

$\text {Possible answers are } \dfrac{23}{99} \ , \dfrac{24}{99} \ , \dfrac{25}{99} \text { and } \dfrac{26}{99}$

3 0

3 years ago