earthquakes, volcanic activity, crustal deformation
I
Training behaviors..........................................
The potential energy is most often referred to as the "energy at rest" and is dependent on the elevation of an object. This can be calculated through the equation,
E = mgh
where E is the potential energy, m is the mass, g is the acceleration due to gravity, and h is the height. In this item, we are not given with the mass of the cart so we assume it to be m. The force is therefore,
E = m(9.8 m/s²)(0.5 m) = 4.9m
Hence, the potential energy is equal to 4.9m.
Answer:
D = 104.4 m
Explanation:
We are given two displacement vectors. One in north direction other in east direction. We know that north and east directions are perpendicular to each other. Hence, the displacements vectors are also perpendicular to each other. Therefore, there resultant can be found by using Pythagora's Theorem like rectangular components method.
D = √(Dₓ² + Dy²)
where,
D = Magnitude of vector sum of both displacements = ?
Dₓ = Magnitude of Displacement Vector in east direction = 30 m
Dy = Magnitude of Displacement Vector in North Direction = 100 m
Therefore,
D = √[(30 m)² + (100 m)²]
<u>D = 104.4 m</u>