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kolbaska11 [484]
3 years ago
12

Four locations on Earth receive sunlight at different angles. At which of the following angles will the intensity of sunlight re

ceived be the greatest? 90° 75° 50° 25°
Physics
2 answers:
lisov135 [29]3 years ago
4 0

Answer:

90 degrees

Explanation:

cause its the highest

Pepsi [2]3 years ago
3 0
I believe 90 degrees
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A plane electromagnetic wave, with wavelength 5 m, travels in vacuum in the positive x direction with its electric vector E, of
Dafna1 [17]

Answer:

Explanation:

E₀ = 229.1 V/m

E = E₀ / √2 = 229.1 / 1.414 = 162 V/m

B =  E / c  ( c is velocity of em waves )

=   162 / (3 x 10⁸)  = 54 x 10⁻⁸ T

rate of energy flow =  ( E x B )  / μ₀

= 162 x 54 x 10⁻⁸ / 4π x 10⁻⁷

= 69.65 W per m².

5 0
3 years ago
If i hold a glass full of air upside down, and i take it to the bottom of the swimming pool without tipping it, the density (thi
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6 0
3 years ago
A car is moving in uniform circular motion. If the car's speed were to double to keep the car moving with the same radius, the a
Anestetic [448]

Answer:

Increase by a factor of 4.

Explanation:

The acceleration of a car moving with speed v in a circle of radius R is given by:

a=\frac{v^2}{R}.

Now if we double the speed v in the equation above, it becomes 2v. Thus:

a=\frac{v^2}{R}\:\: {\rightarrow}\:\: a_n=\frac{(2v)^2}{R}=4\frac{v^2}{R}=4a.

Therefore the acceleration is increased by a factor of 4.

7 0
3 years ago
What is quantic fisic
Elodia [21]

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3 0
3 years ago
A 0.140 kg baseball is thrown horizontally with a velocity of 28.9 m/s. It is struck with a constant horizontal force that lasts
Viefleur [7K]

Answer:

4987N

Explanation:

Step 1:

Data obtained from the question include:

Mass (m) = 0.140 kg

Initial velocity (U) = 28.9 m/s

Time (t) = 1.85 ms = 1.85x10^-3s

Final velocity (V) = 37.0 m/s

Force (F) =?

Step 2:

Determination of the magnitude of the horizontal force applied. This can be obtained by applying the formula:

F = m(V + U) /t

F = 0.140(37+ 28.9) /1.85x10^-3

F = 9.226/1.85x10^-3

F = 4987N

Therefore, the magnitude of the horizontal force applied is 4987N

8 0
3 years ago
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