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kolbaska11 [484]
4 years ago
12

Four locations on Earth receive sunlight at different angles. At which of the following angles will the intensity of sunlight re

ceived be the greatest? 90° 75° 50° 25°
Physics
2 answers:
lisov135 [29]4 years ago
4 0

Answer:

90 degrees

Explanation:

cause its the highest

Pepsi [2]4 years ago
3 0
I believe 90 degrees
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How many joules of energy are required to accelerate one kilogram of mass from rest to a velocity of 0.866c?
Arlecino [84]

Answer:

the amount of energy needed is 1.8 x 10¹⁷ J.

Explanation:

Given;

mass of the object, m₀ = 1 kg

velocity of the object, v = 0.866 c

By physics convection, c is the speed of light = 3 x 10⁸ m/s

The energy needed is calculated as follows;

E = Mc²

As the object approaches the speed of light, the change in the mass of the object is given by Einstein's relativity formula;

M = \frac{M_0}{\sqrt{1- \frac{v^2}{c^2} } } \\\\  M = \frac{1}{\sqrt{1- \frac{(0.866c)^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{1- \frac{0.74996c^2}{c^2} } }\\\\  M = \frac{1}{\sqrt{0.25} } \\\\ M = 2 \ kg

The energy required is calculated as;

E = 2 x (3 x 10⁸)²

E = 1.8 x 10¹⁷ J

Therefore, the amount of energy needed is 1.8 x 10¹⁷ J.

3 0
3 years ago
A 2-kg ball is moving with a speed of 4 m/s, and a 4-kg ball is moving with a speed of 2 m/s. What can you conclude about the of
Mila [183]
<h2>Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball</h2>

Explanation:

Kinetic energy = 0.5 x Mass x Velocity²

For ball of mass 2 kg

           Mass, m = 2 kg

           Velocity, v = 4 m/s

           Kinetic energy = 0.5 x 2 x 4² = 16 J

For ball of mass 4 kg

           Mass, m = 4 kg

           Velocity, v = 2 m/s

           Kinetic energy = 0.5 x 4 x 2² = 8 J

Kinetic energy of mass 4 kg ball is less than kinetic energy of mass 2 kg ball

4 0
3 years ago
In the figure a block slides along a track from one level to a higher level, by moving through an
Scrat [10]

Answer:

(B) 1.17 m.

Explanation:

At the highest point, the conservation of energy equation would becomes;

K.E (initial ) = K.E + P.E;

½ m(V)^2 = ½ m(V)^2 + mgh

(m*6^2)/2 = (m * 9.81 * 1.1) + (m*V^2)/2

36/2 = (9.81 * 1.1) + v^2/2

Solving the equation;

v=√14.44 m/s  

= 3.8 m/s

a = −0.6g

= -0.6*9.81

= −5.88 m/s^2

Using equation of motion,

V^2 = U^2 + 2aS

S = V^2/2a

= 14.44/12

= 1.19 m.

7 0
4 years ago
Consider a wire of length L =0.30 m that runs north-south on a horizontal surface. There is a current I = 0.50 A flowing north i
jok3333 [9.3K]

Answer:

The size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.

Explanation:

To determine the size of the magnetic force on the wire due to the Earth's magnetic field,

The magnetic force is given by the formula

F = ILB sinθ

Where F is the magnetic force on the wire

I is the electric current in Amperes (A)

L is is the length of wire in meters (m)

B is the magnetic field in Tesla (T)

and θ is the angle between current and magnetic field

From the question,

L = 0.30 m

I = 0.50 A

B = 0.50 gauss = 0.5 × 10⁻⁴ T (NOTE: 1 Gauss = 10⁻⁴ Tesla)

θ = 38°

Now, putting the values into the equation

F = ILB sinθ

F = 0.50 × 0.30 × 0.5 × 10⁻⁴ sin38°

F = 7.5 × 10⁻⁶ (0.61566)

F = 4.62 × 10⁻⁶ N

Hence, the size of the magnetic force on the wire due to the Earth's magnetic field is 4.62 × 10⁻⁶ N.

3 0
4 years ago
A 25 kg object is at rest. Calculate the momentum of the object. ​
USPshnik [31]

Answer:

there is no momentum

Explanation:

if an object is at rest there is no momentum to build, no speed, no acceleration it does not move unless force is acted upon it.

8 0
3 years ago
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