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Rudik [331]
2 years ago
6

What is the angular momentum of a 0.25 kg mass rotating on the end of a piece of

Physics
1 answer:
finlep [7]2 years ago
4 0

L = r x p = rmv = mr²ω

L = 0.25 x 0.75² x 12.5 = 1.758

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A 225 kg block is pulled by two horizontal forces. The first force is 178 N at a 41.7-degree angle and the second is 259 N at a
yawa3891 [41]

Answer:

52.9 N, 364.7 N

Explanation:

First of all, we need to resolve both forces along the x- and y- direction. We have:

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A_x = (178 N)(cos 41.7^{\circ})=132.9 N\\A_y = (178 N)(sin 41.7^{\circ})=118.4 N

- Force B (259 N)

B_x = (259 N)(cos 108^{\circ})=-80.0 N\\B_y = (259 N)(sin 108^{\circ})=246.3 N

So the x- and y- component of the total force acting on the block are:

R_x = A_x + B_x = 132.9 N - 80.0 N =52.9 N\\R_y = A_y + B_y = 118.4 N +246.3 N = 364.7 N

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3 years ago
A major contemporary learning view of personality which holds that personality traits result from a
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21

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Which of the below statements are true?
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Answer:

B

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if you start at point A, then go to point B, and back to point A, the displacement is zero because you started and ended at the same point.

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