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3 years ago

Solve for w: 30= 6/5w

Mathematics

2 answers:

Inga [223]3 years ago

7 0

Answer:

w = 25

(Hope this helps! Btw, I am the first to answer.)

IrinaK [193]3 years ago

4 0

Answer:

$w = \boxed{\frac{1}{25} }$

Step-by-step explanation:

$if \:: 30= \frac{6}{5w} \\ (30) \times (5w) =( 6) \times (1) \\ 5w = \frac{6}{30} \\ 5w = \frac{1}{5} \\ (5) \times (5) \times (w) = (1) \times (1) \\ w = \frac{1}{(5) \times (5)} \\ w = \frac{1}{ {5}^{2} } = \frac{1}{25}$

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A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago

Hey can someone plz help me with this??? *cute eyes*

Leto [7]

Answer:

A. 5

B. -5, 5

C. 5, 5

Step-by-step explanation:

A. |-6+(-1)| = 5

B. -6-(-1)=-6+1=-5

-1-(-6)=-1+6=5

C. |-6-(-1)|=|-6+1|=5

|-1-(-6)|=|-1+6|=5

5 0

3 years ago

Sean has some candy bars that he wants to give away. He is going to give each person \dfrac18 8 1 start fraction, 1, divided b

Afina-wow [57]

Answer:

22 people

Step-by-step explanation:

Sean has 2 3/4 candy bars. That is 11/4 candy bars.

He wants to give out 1/8 candy bars.

The number of people that will get candy is:

$\frac{11}{4} / \frac{1}{8}\\ \\= \frac{\frac{11}{4} }{\frac{1}{8}} \\\\\frac{11}{4} * \frac{8}{1} \\\\22$

22 people can get candy.

8 0

3 years ago

Read 2 more answers

Which equation has no solution?

konstantin123 [22]

Answer:

B) 4x-5-3x=x+5 has no solution.

Step-by-step explanation:

A) 4x+4=4-4x

4x-(-4x)+4=4

4x+4x+4=4

8x+4=4

8x=4-4

8x=0

x=0/8

x=0

------------------

B) 4x-5-3x=x+5

4x-3x-5=x+5

x-5=x+5

x-x-5=5

-5=5

no solution.

------------------------

C) 4x+15-9x=5x+15

4x-9x+15=5x+15

-5x+15=5x+15

-5x-5x+15=15

-10x+15=15

-10x=15-15

-10x=0

x=0/-10

x=0

------------------------

D) 4x+2-x=4+3x-2

3x+2=3x+4-2

3x+2=3x+2

infinitely many solutions.

8 0

2 years ago

five times the sum of the digits of a two digit number is 9 less than the number formed by reversing its digits . if four times

TEA [102]

9514 1404 393

Answer:

Step-by-step explanation:

Let x and y represent the tens and ones digits, respectively. The 5 times the sum of digits is 5(x+y). The value of the digit-reversed number is (10y+x), so the required relation is ...

5(x +y) = (10y +x) -9

The other relationship between the digits is given as ...

4y = 1/2(10x)

A graphing calculator shows the solution to these equations is (x, y) = (4, 5).

The two-digit number is 45.

<em>Additional comment</em>

You can solve these equations in any of a variety of ways. Using a graphing calculator to find integer solutions is fast and easy, so is one of my favorites. Here, the coefficients on one equation are not easy multiples of those in the other, so substitution and/or elimination can get messy. In this situation, I like to use the "cross-multiplication" method, which starts with the equations in general form:

4x -5y +9 = 0
5x -4y +0 = 0

From the coefficients of these equations, differences of cross products are formed:

d1 = 4(-4) -(5)(-5) = 9
d2 = -5(0) -(-4)(9) = 36
d3 = 9(5) -0(4) = 45

Then the solutions are the solutions to 1/d1 = x/d2 = y/d3:

x = d2/d1 = 36/9 = 4
y= d3/d1 = 45/9 = 5

(x, y) = (4, 5) ⇒ the number is 45.

This method is one of several variations of Cramer's Rule, the general solution of systems of linear equations using matrix methods.

7 0

3 years ago