Answer:
4cotα=tanα
4(1/tanα)=tanα
(4/tanα)=tanα
cross multiply
=> 4=tan²α
√4=√tan²α
±2=tanα
α=arc( tan) |2|
α=63.4° ( in first quadrant)
and
α=180+63.4=243.4 in the third quadrant
since we also found a negative answer( i.e –2) then α also lies in quadrants where it gives a negative value(i.e second and fourth quadrants)
α=180–63.4=116.6° in the second quadrant
α=360–63.4=296.6 in the fourth quadrant
therefore theta( in my case, alpha) lies in all four quadrants and is equal to:
α=63.4°,243.4°,116.6°and 296.6°
First,
The volume is given by the integral (one of 6 possible combinations),
What is the volume of a cube with a side length of 2/5 cm? 0.4 cm
A.)
x y
1 1
2 4
3 9
dx=2-1→dx=1 dy=4-1→dy=3
dx=3-2→dx=1 dy=9-4→dy=5 different to 3, then this table can not be represented by a line
B.)
x y
1 2
2 5
3 10
dx=2-1→dx=1 dy=5-2→dy=3
dx=3-2→dx=1 dy=10-5→dy=5 different to 3, then this table can not be represented by a line
C.)
x y
1 3
2 6
3 9
dx=2-1→dx=1 dy=6-3→dy=3
dx=3-2→dx=1 dy=9-6→dy=3, then this table can be represented by a line
D.)
x y
1 0
2 3
3 8
dx=2-1→dx=1 dy=3-0→dy=3
dx=3-2→dx=1 dy=8-3→dy=5 different to 3, then this table can not be represented by a line
Answer: Option C. x 1 2 3 y 3 6 9
