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GenaCL600 [577]
2 years ago
11

Valerie deposits $1,900 in an account that

Mathematics
1 answer:
horrorfan [7]2 years ago
5 0

Answer:

$2273.19

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

<u>Algebra I</u>

Compound Interest Rate Formula: \displaystyle A = P(1 + \frac{r}{n})^{nt}

  • A is final amount
  • P is principle amount
  • r is rate
  • n is compound rate
  • t is time (in years)

Step-by-step explanation:

<u>Step 1: Identify Variables</u>

P = $1900

r = 3% = 0.03

n = 4

<u>Step 2: Solve for </u><em><u>A</u></em>

  1. Substitute [CIRF]:                    \displaystyle A = 1900(1 + \frac{0.03}{4})^{4(6)}
  2. (Parenthesis) Divide:              \displaystyle A = 1900(1 + 0.0075)^{4(6)}
  3. (Parenthesis) Add:                  \displaystyle A = 1900(1.0075)^{4(6)}
  4. (Exponents) Multiply:             \displaystyle A = 1900(1.0075)^{24}
  5. Exponents:                             \displaystyle A = 1900(1.19641)
  6. Multiply:                                  \displaystyle A = 2273.19
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Answer:

The data table is attached below.

Step-by-step explanation:

The average of a set of data is the value that is a representative of the entire data set.

The formula to compute averages is:

\bar x=\frac{1}{n}\sum\limits^{n}_{i=1}{x_{i}}

Compute the average for drop 1 as follows:

\bar x_{1}=\frac{1}{3}\times[10+11+9]=10

Compute the average for drop 2 as follows:

\bar x_{2}=\frac{1}{3}\times[29+31+30]=30

Compute the average for drop 3 as follows:

\bar x_{3}=\frac{1}{3}\times[59+58+61]=59.33

Compute the average for drop 4 as follows:

\bar x_{4}=\frac{1}{3}\times[102+100+98]=100

Compute the average for drop 5 as follows:

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The data table is attached below.

3 0
3 years ago
Use Newton’s Method to find the solution to x^3+1=2x+3 use x_1=2 and find x_4 accurate to six decimal places. Hint use x^3-2x-2=
luda_lava [24]

Let f(x) = x^3 - 2x - 2. Then differentiating, we get

f'(x) = 3x^2 - 2

We approximate f(x) at x_1=2 with the tangent line,

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The x-intercept for this approximation will be our next approximation for the root,

10x - 18 = 0 \implies x_2 = \dfrac95

Repeat this process. Approximate f(x) at x_2 = \frac95.

f(x) \approx f(x_2) + f'(x_2) (x-x_2) = \dfrac{193}{25}x - \dfrac{1708}{125}

Then

\dfrac{193}{25}x - \dfrac{1708}{125} = 0 \implies x_3 = \dfrac{1708}{965}

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f(x) \approx f(x_3) + f'(x_3) (x - x_3) = \dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125}

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\dfrac{6,889,342}{931,225}x - \dfrac{11,762,638,074}{898,632,125} = 0 \\\\ \implies x_4 = \dfrac{5,881,319,037}{3,324,107,515} \approx 1.769292663 \approx \boxed{1.769293}

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