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Ira Lisetskai [31]
2 years ago
7

Two objects perform the same task. One has thousands of moving parts while the other has no moving parts. What are they?.

Physics
1 answer:
Natalka [10]2 years ago
5 0

The two objects perform the same task of measuring time and they are hourglass and sundial.

<h3>What is an hourglass?</h3>

An hourglass is a device used to measure the passage of time.

The hourglass contains two glass bulbs connected vertically by a narrow neck that allows a regulated flow of a substance from the upper bulb to the lower one.

<h3>What is a sundial?</h3>

A sundial is a horological device that is used to measure time of the day when there is sunlight by the apparent position of the Sun in the sky. Unlike hourglass, its doesn't move.

Thus, the two objects perform the same task of measuring time and they are hourglass and sundial.

Learn more about time measurement here: brainly.com/question/13893070

#SPJ1

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A spring of force constant 285.0 N/m and unstretched length 0.230 m is stretched by two forces, pulling in opposite directions a
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from the question you can see that some detail is missing, using search engines i was able to get a similar question on "https://www.slader.com/discussion/question/a-student-throws-a-water-balloon-vertically-downward-from-the-top-of-a-building-the-balloon-leaves-t/"

here is the question : A student throws a water balloon vertically downward from the top of a building. The balloon leaves the thrower's hand with a speed of 60.0m/s. Air resistance may be ignored,so the water balloon is in free fall after it leaves the throwers hand. a) What is its speed after falling for 2.00s? b) How far does it fall in 2.00s? c) What is the magnitude of its velocity after falling 10.0m?

Answer:

(A) 26 m/s

(B) 32.4 m

(C) v = 15.4 m/s

Explanation:

initial speed (u) = 6.4 m/s

acceleration due to gravity (a) = 9.9 m/s^[2}

time (t) = 2 s

(A)   What is its speed after falling for 2.00s?

  from the equation of motion v = u + at we can get the speed

v = 6.4 + (9.8 x 2) = 26 m/s

(B) How far does it fall in 2.00s?

  from the equation of motion s=ut+0.5at^{2} we can get the distance covered

s = (6.4 x 2) + (0.5 x 9.8 x 2 x 2)

s = 12.8 + 19.6 = 32.4 m

c) What is the magnitude of its velocity after falling 10.0m?

from the equation of motion below we can get the velocity

v^{2} = u^{2} + 2as\\v^{2} = 6.4^{2} + (2x9.8x10)\\V^{2} = 236.96\\v = \sqrt{236.96}

v = 15.4 m/s

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