I drop an egg from a certain distance and it takes 3.74 seconds to reach the ground. How high up was the egg?
1 answer:
Answer:
68.5 meters
Explanation:
Given:
v₀ = 0 m/s
a = 9.8 m/s²
t = 3.74 s
Find: Δy
Δy = v₀ t + ½ at²
Δy = (0) (3.74) + ½ (9.8) (3.74)²
Δy = 68.5
The egg fell 68.5 meters.
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