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Dmitry_Shevchenko [17]
3 years ago
11

True or false. there would be no like in earth without the sun

Physics
1 answer:
alisha [4.7K]3 years ago
6 0

hello!

True

have a goed day

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A 68 kg crate is dragged across a floor by pulling on a rope attached to the crate and inclined 13° above the horizontal. (a) if
Blababa [14]
<span>Answer: Therefore, x component: Tcos(24°) - f = 0 y component: N + Tsin(24°) - mg = 0 The two equations I get from this are: f = Tcos(24°) N = mg - Tsin(24°) In order for the crate to move, the friction force has to be greater than the normal force multiplied by the static coefficient, so... Tcos(24°) = 0.47 * (mg - Tsin(24°)) From all that I can get the equation I need for the tension, which, after some algebraic manipulation, yields: T = (mg * static coefficient) / (cos(24°) + sin(24°) * static coefficient) Then plugging in the values... T = 283.52. Reference https://www.physicsforums.com/threads/difficulty-with-force-problems-involving-friction.111768/</span>
7 0
3 years ago
a lump of putty and a rubber ball have equal mass. both are thrown with equal speed against a wall. the putty sticks to the wall
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The bouncy ball experiences the greater momentum change.

To understand why, you need to remember that momentum is actually
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The putty and the ball have the same mass, and you throw them
with the same speed.  So, on the way from your hand to the wall,
they both have the same momentum.
Call it " M in the direction toward the wall ".

After they both hit the wall:

-- The putty has zero momentum.
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-- The ball has momentum of " M in the direction away from the wall ".
    Its momentum changed by an amount of  2M .
5 0
3 years ago
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A particle of mass 2 g travel a distance of 12 m in a time travel of 2 minute assuming the speed was constant find its kinetic e
balandron [24]

Answer:

0.00001 J

Explanation:

k.e =  \frac{1}{2} m {v}^{2}  \\  =  \frac{1}{2} (0.002) { ( \frac{12}{120} )} ^{2}  \\  = 0.00001j

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If external is force applied

Explanation:

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