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bazaltina [42]
3 years ago
5

Name the type of software which provides the user interface. [1 mark

Computers and Technology
1 answer:
Inessa [10]3 years ago
7 0

Explanation:

user interface, also sometimes called a human-computer interface, comprises both hardware and software components. It handles the interaction between the user and the system.

There are different ways of interacting with computer systems which have evolved over the years. There are five main types of user interface:

command line (cli)

graphical user interface (GUI)

menu driven (mdi)

form based (fbi)

natural language (nli)

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Write a c program that reprints input so that no line is longer than 50 characters. Specifically, for lines less than or equal t
Alex73 [517]

Using the knowledge in computational language in C++ it is possible to write a code that reprints prints input so that no line is longer than 50 characters.

<h3>Writting the code:</h3>

<em>#include<stdio.h></em>

<em />

<em>int main(int argc, char** argv){</em>

<em>    //creating pointer to read a file</em>

<em>    FILE * fp;</em>

<em>    char * line = NULL;</em>

<em>    size_t len = 0;</em>

<em>    ssize_t read;</em>

<em>    int i=0;</em>

<em>    //opening a file</em>

<em>    fp = fopen(argv[1], "r");</em>

<em>    //handling the error condition</em>

<em>    if (fp == NULL){</em>

<em>        printf("File not found..!!");</em>

<em>        return 0;</em>

<em>    }</em>

<em>    int moreThan50 =0;</em>

<em>    //reading a file line by line</em>

<em>    while ((read = getline(&line, &len, fp)) != -1) {</em>

<em>        i = 0;</em>

<em>        if(read >= 50){</em>

<em>            moreThan50++;</em>

<em>        }</em>

<em>        while(i < read){</em>

<em>            if(line[i]!='\n'){</em>

<em>                if(i%50 == 0){</em>

<em>                    printf("\n%c",line[i]);</em>

<em>                }else{</em>

<em>                    printf("%c",line[i]);</em>

<em>                }</em>

<em>            }</em>

<em>            i++;</em>

<em>        }</em>

<em>    }</em>

<em>    printf("\nTotal lines over 50 chars: %d\n",moreThan50);</em>

<em>    printf("Offending Lines: ");</em>

<em>    for(i=1;i<=moreThan50;i++)</em>

<em>        printf("%d, ",i);</em>

<em>    fclose(fp);</em>

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dimaraw [331]

Answer:

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Explanation:

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