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xenn [34]
3 years ago
14

PLEASE HELP! How are the following aspects of a reaction affected by the addition of a catalyst?

Chemistry
1 answer:
aivan3 [116]3 years ago
5 0
If you add a catalyst to a reaction, the activation energy of the forward and reverse reaction should decrease which is shown by the energy diagram of the reaction which has a smaller peak with a catalyst and the rates of the forward and reverse reaction should increase.

The fact that both the forward and reverse reactions are affected in the same way is shown by the fact that the addition of a catalyst does not affect the equilibrium state of the reaction.
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Balanced chemical for hydrochloride acid and sodium hydroxide
VARVARA [1.3K]
HCl+NaOH-->NaCl+H2O.
7 0
4 years ago
Andrea and the other members of the tennis team are practicing hitting tennis balls. If two people hit identical balls at the sa
almond37 [142]

Answer:

D

Explanation:

The formula for calculating kinetic energy is 1/2mv^2, where m is the mass and v is the velocity or speed of the object. Since all of the balls have the same mass, the one with the highest speed or velocity will have the highest kinetic energy. Hope this helps!

8 0
3 years ago
If given the mole fraction of water in an aqueous sucrose (C12H22O11) solution and asked to calculate the molality of the soluti
olasank [31]

Answer:

No additional information is required in order to calculate the molality of the solution.

Explanation:

Mole fraction of water = \chi_1

Mole fraction of sucrose = \chi_2

\chi_1+\chi_2=1

From the given mole fraction of water mole fraction of sucrose can be determined.

And from both values of mole fraction moles of water and sucrose can also be calculated.

\chi_1=\frac{n_1}{n_1+n_2}

\chi_2=\frac{n_2}{n_1+n_2}

After calculating the moles of water convert them into mass of water in grams and then change that into kilograms say that be M'.

Finally we can determine the molality of solution ;

Molality=\frac{\text{Moles of compound}}{\text{mass of solvent (kg)}}

Molality of the sucrose solution ;

m=\frac{n_1}{M'}

From this we can conclude that no additional information is required in order to calculate the molality of the solution.

7 0
3 years ago
The reaction of carboxylic acids with alcohol in the presence of an acid catalyst yields Select one: amides O esters O no reacti
kumpel [21]

Answer:

esters

Explanation:

The -OR group of the alcohol replaces the -OH of the carboxylic acid, forming an ester. See attachment for condensed mechanism.

4 0
3 years ago
Which of the following is NOT a "big idea" in chemistry?
aalyn [17]
B but im not sure if im 100% correcr
8 0
3 years ago
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