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Alisiya [41]
3 years ago
5

**25 POINTS**. I doubt anyone will do this but it's worth a try to ask. To do this exercise, you will need fifteen containers, f

ive large, five medium, and five small. The "large" containers should be about the size of a soda pop can. The containers do not have to be transparent but they need to be shaped so that you will be able to easily pour water from them into a graduated cylinder. You will also need at least one 100-mL graduated cylinder. Ideally, you will also have a larger and smaller cylinder to use. (If, perhaps, you are using kitchen measuring cups instead of graduated cylinders, they need to have metric markings on them. Be sure to use the metric markings!) Be sure to read the volumes at eye level and at the bottom of the meniscus.
Make a supply of colored water to use in this experiment. Colored water will make it easier to read the meniscus.
Before you start, make a chart in which to record your estimates and actual values. You will also need your phone to take a picture of the large, medium, and small containers you are using to estimate the volume of water, as well as a picture of the graduated container you are using for the actual measurement.
Fill one of the large unmarked containers with colored water, estimate the volume in milliliters (mL) and put it into your chart.
Then carefully pour it into the graduated container to measure the actual water volume. Put the measurement into your chart.
Repeat this procedure with the other four "large" containers. When you have completed this task with the large containers, move on to the medium and small containers.
For the large containers, record your estimated volumes first, then determine the actual volumes and record these figures. Include the pictures that you took. For the medium containers, record your estimated volumes first, then determine the actual volumes and record these figures. Include the pictures that you took.
For the small containers, record your estimated volumes first, then determine the actual volumes and record these figures. Include the pictures that you took.
Chemistry
1 answer:
Travka [436]3 years ago
6 0

Answer:

done not that hard

Explanation:

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Blizzard [7]

Answer:

lol good luck

Explanation:

6 0
3 years ago
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Is 2OH−+Ca2+−>2Ca(OH)2 balanced
wariber [46]

Answer:

No.

Explanation:

No.  There is 1 atom of Ca on the left and 2 Ca's on the right  and 2 OH's on the left and 4 on the right.

The balanced equation is:

4OH-  +  2Ca2+ ---->  2Ca(OH)2.

3 0
3 years ago
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POINTS 50 - 30!!! in my bio to find some of my unanswered questions
alex41 [277]

Answer:

I have answered all 9/10 + this one so 10/10

Explanation:

6 0
2 years ago
Using the following equation 5KNO2+2KMnO4+3H2SO4=5KNO3+2MnSO4+K2SO4+3H20. Starting with 2.47 grams of KNO2 and excess KMnO4 how
Aleonysh [2.5K]

Given equation : 5KNO_{2} + 2KMnO_{4} + 3H_{2}SO_{4}\rightarrow 5KNO_{3} + 2MnSO_{4} + K_{2}SO_{4} + 3H_{2}O

Given information = 2.47 grams KNO2 and excess KMnO4 and we need to find grams of water (H2O).

Since KMnO4 is in excess, so grams of water(H2O) can be calculated using grams of KNO2 with the help of stoichiometry.

To find grams of water(H2O) from grams of KNO2 , we need to follow three steps.

Step 1. Convert 2.47 grams of KNO2 to moles of KNO2.

Moles = \frac{grams}{molar mass}

Molar mass of KNO2 = 85.10 g/mol

Moles = 2.47 gram KNO2\times \frac{1 mol KNO2}{85.10 gram KNO2}

Moles = 0.0290 mol KNO2

Step 2. Convert moles of KNO2 to moles of H2O using mole ratio.

Mole ratio are the coefficient present in front of the compound in the balanced equation.

Mole ratio of KNO2 : H2O is 5 : 3 (5 coefficient of KNO2 and 3 coefficient of H2O)

0.0290 mol KNO2\times \frac{3 mol H2O}{5 mol KNO2}

Mole = 0.0174 mol H2O

Step 3. Convert mole of H2O to grams of H2O

Grams = Moles X molar mass

Molar mass of H2O = 18.00 g/mol

Grams = 0.0174 mol H2O\times \frac{18 g H2O}{1 mol H2O}

Grams of water = 0.313 grams H2O

Summary : The above three steps can also be done in a singe setup as shown below.

2.47 gram KNO2\times \frac{(1 mol KNO2)}{(85.10 gram KNO2)}\times \frac{(3 mol H2O)}{(5 mol KNO2)}\times \frac{(18.00 gram H2O)}{(1mol H2O)}

In the above setup similar units get cancelled out and we will get grams of H2O as 0.313 grams water (H2O)

8 0
4 years ago
A sample of 1L of gas in a container at-73C has a pressure of 32.2inHg. To
Goryan [66]

Answer:

Like you, like you

Like you, ooh

I found it hard to find someone like you

Like you, like you

Send your location, come through

I can't sleep no more

In my head, we belong

And I can't be without you

Why can't I find no one like you?

I can't sleep no more

In my head, we belong

And I can't be without you

Why can't I find no one like you?

Explanation:

8 0
3 years ago
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