<span>There are few main factors affecting the atomic radii, the outermost electrons and the protons in the nucleus and also the shielding of the internal electrons. I would speculate that the difference in radii is given by the electron clouds since the electrons difference in these two elements is in the d orbital and both has at least 1 electron in the 4s (this 4s electron is the outermost electron in all the transition metals of this period). The atomic radio will be mostly dependent of these 4s electrons than in the d electrons. Besides that, you can see that increasing the atomic number will increase the number of protons in the nucleus decreasing the ratio of the atoms along a period. The Cu is an exception and will accommodate one of the 4s electrons in the p orbital.
</span><span>Regarding the density you can find the density of Cu = 8.96g/cm3 and vanadium = 6.0g/cm3. This also correlates with the idea that if these two atoms have similar volume and one has more mass (more protons; density is the relationship between m/V), then a bigger mass for a similar volume will result in a bigger density.</span>
Ionic Bond, which is the transfer of electrons of a metal to a non-metal.
<em>Answer:</em>
4) the one that is reduced, which is the oxidizing agent
<em>Explanation:</em>
<em>An oxidizing agent is one that causes oxidation by gaining electrons from another atom/molecule. </em>
Answer:
nonmetals
Explanation:
nonmetals nonmetals receive more because metals are much harder to gain than nonmetals.
The speed and wavelength changes as a waves travels to a different depth. Slower and bigger amplitudes in shallower depths. Freq does not change
