If the traits for white fur and red eyes were always inherited together then the hypothesis would not have been supported by the data.
Explanation:
The white fur and red eyed mouse had genotype AA RR or AaRr
The black fur mouse and black eye mouse had genotype aarr
The F1 offspring will have all offspring with same phenotype as shown in the Punett square.
AR AR
ar AaRr AaRr
ar AaRr AaRr
all the siblings are of same phenotype
Punnet square to show that genes assort independently.
Ar AR
ar Aarr AaRr 2 white fur and black eye: 2 white fur red eye
ar Aarr AaRr
The phenotype pattern of this punnet square shows that white fur and red eyes are not always inherited.
The law of independent assortment is shown from the cross that is by selfing.
AR Ar aR ar
AR AARR AARr AaAR AaRr
Ar AARr AArr AaRr Aarr
aR AaRR aArR aaRR aaRr
ar AaRr Aarr aaRr aarr
phenotype ratio of 9:3:3:1
9 WHITE FUR RED EYE
3 WHITE FUR BLACK EYE
3 BLACK FUR RED EYE.
1 BLACK FUR BLACK EYE
By cross checking, the options given it is concluded that the traits for white fur and red eyes are not always inherited together, the two traits are governed by different genes and are independently exhibited in the individual as stated in law of independent Assortment.
1- starts with bare rock
2- takes longer than Secondary succession
3- Volcanic eruptions, glaciers, explosions etc are some ways it starts
4- starts after a disturbance
5- it’s the process of changes in an ecosystem
I hope those are good!
Answer:
I think the question is "How might an RNA-based genome results display an increased in infection rate?" because current statement doesn't convey a message clearly.
Explanation:
To answer this question, we need to understand first that what is gene expression. Gene expression is a process in which genetic information is transcribed first to RNA and then into proteins. During transcription stage, only active genes would be transcribed to RNA and all other DNA material don't transcribe at all. Now, if there is an infection, host cell would express only those genes which would actively take part in the defense mechanism, e.g. R-genes, genes involved in production of reactive oxygen species, etc. Hence, to monitor the infection rate, we will look at the RNA-based genome. To do this, we will extract the total RNA and then would sequence it. Then we will annotate the genes and check the relative abundance (differential expression). Finally, we would have a clear that these genes were active against the infection. By doing temporal sampling and sequencing, we would be able to measure the rate as well.
For the second part, potential complications that could arise in doing analysis is the lower amount of RNA, or rapid degradation of RNA in case of presence of RNAses. RNA can be degraded easily at room temperature.
The official term is a megaflash :)
Answer:
2/4
Explanation:
because the ratio off the offspring is 2 black pig : 2 white pig. so probability of white pig will be 2/4.
