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Pani-rosa [81]
3 years ago
10

How much power does it take to lift a 50 N object 10 m high in 20 seconds? | and the units.

Physics
1 answer:
Verdich [7]3 years ago
5 0

Answer:

\boxed {\boxed {\sf 25 \ Watts}}

Explanation:

Power is the work done divided by the time. It can be found using the following formula.

P=\frac{F*D}{T}

The force is 50 Newtons, the distance is 10 meters, and the time is 20 seconds.

F= 50 \ N \\D= 10 \ m \\T= 20 \ s

Substitute the values into the formula.

P=\frac{50 \ N * 10 \ m}{20 \ s }

Multiply the numerator first.

P=\frac{500 \ N*m}{20 \ s}

  • 1 Newton meter is equal to 1 Joule.
  • Therefore, the numerator is equal to 500 Joules.

P= \frac{500 \ J}{20 \ s}

Divide.

P= 25 \ J/s

  • 1 Joule per second is equal to 1 Watt.
  • Our answer is equal to 25 W

P= 25 \ W

It takes <u>25 Watts</u><u> </u>to lift a 50 Newton object 10 meters high in 20 seconds.

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zhannawk [14.2K]

Answer:

Final speed of car = 12 m/s

Explanation:

We have equation of motion v = u + at, where v is final velocity, u is initial velocity, a is acceleration and t is time.

a) A cart starts from rest and accelerates at 4.0 m/s² for 5.0 s

        v = ?

        u = 0 m/s

        a = 4.0 m/s²

         t = 5 s

         v = u + at = 0 + 4 x 5 = 20 m/s

b) Then maintains that velocity for 10 s

        v = ?

        u = 20 m/s

        a = 0 m/s²

         t = 10 s

         v = u + at = 20 + 0 x 10 = 20 m/s

c) Then decelerates at the rate of 2.0 m/s² for 4.0 s

        v = ?

        u = 20 m/s

        a = -2.0 m/s²

         t = 4 s

         v = u + at = 20 + -2 x 4 = 12 m/s

Final speed of car = 12 m/s

3 0
3 years ago
5. If 100N effort is required to lift a load of 300N in a lever of 1m and distance between fulcrums to load is 30 cm then, calcu
pishuonlain [190]

effort distance =?

effort =100N

load =300N

lever =1m

load D =30cm

ma=?

vr=?

efficiency =?

we know that

effort distance =l ×ld

= 300×30

9000

ma= l ×e

= 100×300

= 30000

vr = ld ×ed

= 1×9000

=9000

efficiency =(ma÷vr)/100

(30000÷9000)×100

3.33×100

333

5 0
3 years ago
In an evironmental system of subsystem, the mass balance equation is:__________.
kolbaska11 [484]

Answer:

Explanation:

The mass balance is an application of conservation of mass, to the analysis of physical system. This is given in an equation form as

Input = Output + Accumulation

The conservation law that is used in this analysis of the system actually depends on the context of the problem. Nevertheless, they all revolve around conservation of mass. By conservation of mass, I mean that the fact that matter cannot disappear or be created spontaneously.

8 0
4 years ago
Chemical vapor deposition can be defined as the interaction between a mixture of gases and the surface of a heated substrate, ca
Valentin [98]

Answer: The given statement is true.

Explanation:

When a substrate is exposed to one more more number of volatile substances that react together on the surface of substrate to produce a suitable deposit of a thin non-volatile film is known as chemical vapor deposition.

This type of reaction generally occurs in heat flux.

Therefore, we can conclude that the statement chemical vapor deposition can be defined as the interaction between a mixture of gases and the surface of a heated substrate, causing chemical decomposition of some of the gas constituents and formation of a solid film on the substrate, is true.

5 0
3 years ago
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salantis [7]

(B)

Explanation:

pe =  \frac{1}{2} k {x}^{2}

3 0
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