1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
ValentinkaMS [17]
3 years ago
6

A car travels due east with a speed of 38.0 km/h. Raindrops are falling at a constant speed vertically with respect to the Earth

. The traces of the rain on the side windows of the car make an angle of 72.0° with the vertical. Find the velocity of the rain with respect to the following reference frames. (Enter the magnitude of the velocity.)
Physics
1 answer:
DiKsa [7]3 years ago
3 0

Answer: 116.926 km/h

Explanation:

To solve this we need to analise the relation between the car and the Raindrops. The cars moves on the horizontal plane with a constant velocity.

Car's Velocity (Vc) = 38 km/h

The rain is falling perpedincular to the horizontal on the Y-axis. We dont know the velocity.

However, the rain's traces on the side windows makes an angle of 72.0° degrees. ∅ = 72°

There is a relation between this angle and the two velocities. If the car was on rest, we will see that the angle is equal to 90° because the rain is falling perpendicular. In the other end, a static object next to a moving car shows a horizontal trace, so we can use a trigonometric relation on this case.

The following equation can be use to relate the angle and the two vectors.

Tangent (∅) = Opposite (o) / adjacent (a)

Where the Opposite will be the Rain's Vector that define its velocity and the adjacent will be the Car's Velocity Vector.

Tan(72°) = Rain's Velocity / Car's Velocity

We can searching for the Rain's Velocity

Tan(72°) * Vc = Rain's Velocity

Rain's Velocity = 116.926 km/h

You might be interested in
What is a neutral atom?
IgorC [24]
A neutral atom is simply an atom that has no charge.
8 0
3 years ago
Read 2 more answers
A car battery has a rating of 250 ampere-hours. This rating is one indication of the total charge that the battery can provide t
Serga [27]

Answer:

Total charge provided by the battery could be 900000 C.

Maximum current provided by the battery for 37 minutes could be 405.405 A

Explanation:

Rating= 250 A-h

a. Total charge:

Rating=Q/t\\Q=Rating.t\\

Suppose t=1h

Q=250 A(1h)\\Q=250 A(3600 sec)\\Q= 900000 A.sec

We konw that Ampere=\frac{Coulomb}{sec}, replacing:

Q=900000(\frac{Coulomb}{sec})(sec)\\Q=900000 Coulomb

Total charge provided by the battery could be 900000 C.

b. Maximum current for 37 minutes

I=\frac{Q}{t} \\I=\frac{900000 C}{37*60 sec}\\I=405.405 A

Maximum current provided by the battery for 37 minutes could be 405.405 A

4 0
3 years ago
What causes breakers?
nata0808 [166]

Answer:

nreaker

Explanation:

A switch that automatically interrupts or shuts off an electric current at the first indication of a overload

3 0
3 years ago
Calcular la resistencia de una varilla de grafito de 170 cm de longitud y 60 mm2. Resistividad grafito 3,5 10-5 Ωm
ozzi

Answer:

R = 0.992 Ω

Explanation:

En esta pregunta, dada la información que contiene, debemos calcular la resistencia de la varilla de grafito.

Matemáticamente,

Resistencia = (resistividad * longitud) / Área De la pregunta;

Resistividad = 3,5 * 10 ^ -5 Ωm

longitud = 170 cm = 1,7 m

Área = 60 mm ^ 2 = 60/1000000 = 6 * 10 ^ -5 m ^ 2

Conectando estos valores a la ecuación anterior, tenemos;

Resistencia = (3.5 * 10 ^ -5 * 1.7) / (6 * 10 ^ -5) =

(3.5 * 1.7) / 6 = 0.992 Ω

3 0
3 years ago
To start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of 290 m/s at 57.0° above the ho
cupoosta [38]

Answer:

xf = 5.68 × 10³ m  

yf = 8.57 × 10³ m  

Explanation:

given data

vi = 290 m/s

θ = 57.0°

t = 36.0 s

solution

firsa we get here origin (0,0) to where the shell is launched

xi = 0                            yi = 0

xf = ?                            yf = ?

vxi =  vicosθ               vyi = visinθ  

ax = 0                          ay = −9.8 m/s

now we solve x motion: that is

xf = xi + vxi × t + 0.5 × ax × t²     ............1

simplfy it we get

xf = 0 + vicosθ × t + 0

put here value and we get

xf = 0 + (290 m/s) cos(57) (36.0 s)

xf = 5.68 × 10³ m  

and

now we solve for y motion: that is

yf = yi + vyi × t + 0.5 × ay × t ²     ............2

put here value and we get

yf = 0 + (290 m/s) × sin(57) × (36.0 s) + 0.5 × (−9.8 m/s2) × (36.0 s)  ²

yf = 8.57 × 10³ m  

5 0
3 years ago
Other questions:
  • A man begins pushing a lwan mower across a lawn from a standing start. Which is true? A. The man is decreasing the kinetic energ
    9·1 answer
  • How does Connecticut energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling
    6·1 answer
  • Spinning situations???
    13·2 answers
  • 25% part (c) assume that d is the distance the cheetah is away from the gazelle when it reaches full speed. Derive an expression
    13·1 answer
  • You push a 1.00 food tray through the cafeteria One
    10·1 answer
  • Three identical resistors are connected in parallel to a battery. If the current of 12. A flows from the battery, how much curre
    10·1 answer
  • 1 kg ball rolls off a 33 m high cliff, and lands 23 m from the base of the cliff. Express the displacement and the gravitational
    7·1 answer
  • How does energy from the Sun travel to Earth?
    12·2 answers
  • Why is Joshuas head so big?
    6·1 answer
  • a standby generator is connected to 1540 w lamps and a musicians 600w amplifying system how much energy is used if the generator
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!