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Gwar [14]
3 years ago
14

A 1.5-kg ball is throw at 10 m/s. What is the balls momentum?

Physics
1 answer:
alexdok [17]3 years ago
3 0

Answer : The momentum of ball is, 15 kg.m/s

Explanation :

Momentum : It is defined as the motion of a moving body. Or it is defined as the product of mass of velocity of an object.

Formula of momentum is:

where,  

p = momentum  = ?

m = mass  = 1.5 kg

v = velocity = 10 m/s

Now put all the given values in the above formula, we get:

Therefore, the momentum of ball is 15 kg.m/s

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ΒγΕ the answer should be a hot day

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What is the science behind the making of pop-up books?
IRINA_888 [86]

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Explanation

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6 0
3 years ago
What are the variables of Boyle's law?
vesna_86 [32]

Answer: pressure and volume

Explanation:

Boyle's law states that the volume of a fixed mass of gas is inversely proportional to the pressure of the gas provided temperature is kept constant.

Mathematically, Boyle's law can be explained as: PV = k,

where P is pressure

V is volume, and

k is a constant.

So, increase in the pressure of a gas leads to decrease in its volume and vice versa.

3 0
3 years ago
Calculate the required rate of return for Climax Inc., assuming that (1) investors expect a 4.0% rate of inflation in the future
Westkost [7]

Answer:

Required rate of return = 18.5 %

Explanation:

given,                            

rate of inflection = 4 %

risk free rate = 3 %                      

market risk premium = 5 %                    

firm has a beta  = 2.30                                  

rate of return has averaged 15.0% over the last 5 years

now,                                                                      

Nominal risk free rate = risk free rate  + inflation

                                    = 3%  +  4%

                                   = 7%

Required rate of return = Nominal risk free rate + β (RPM)

                                       = 7%       +          2.3 x 5.0%

Required rate of return = 18.5 %

5 0
3 years ago
A daring 510-N swimmer dives off a cliff with a running horizontal leap. What must her minimum speed be just as she leaves the t
oee [108]

Answer:

v_x = 1.26 m/s

Explanation:

given,

weight of swimmer = 510 N

length of ledge, L = 1.75 m

vertical height of the cliff, h =  9 m

speed of the swimmer = ?

horizontal velocity  of the swimmer should be that much it can cross the wedge.

distance = speed x time

d = v_x × t

1.75 = v_x × t ........(1)

now,time taken by the swimmer to cover 9 m

initial vertical velocity of the swimmer is zero.

using equation of motion for time calculation

s = ut +\dfrac{1}{2}gt^2

9= 0+\dfrac{1}{2}\times 9.8\times t^2

  t² = 1.938

  t = 1.39 s

same time will be taken to cover horizontal distance.

now, from equation 1

1.75 = v_x × 1.39

v_x = 1.26 m/s

horizontal speed of the swimmer is equal to 1.26 m/s

4 0
3 years ago
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