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2 years ago

I alwayse get confused with the fractions and the grouping symbols. can someone plz explain how to solve this kind of problem?

Mathematics

2 answers:

gtnhenbr [62]2 years ago

8 0

Answer:

Step-by-step explanation:

Ok so first you would have to distribute the first side (left of the equal sign) So you would get 5+10m. Then do the next side 1/2 times 8 equals 4 and 1/2 times 20 m. Which is 10m. So 4+10m and 5+10m there for it would be false. They do not equal the same.

saw5 [17]2 years ago

3 0

5( 1 + 2m) = 1/2( 8 + 20m)

5 + 10m = 4 + 10m

5 = 4

There are no solutions

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C. y =

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a.y =

x+1 x 21

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x < 1

-x+ 2 x < 1

b.y = {

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d. y - 1

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x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

s-x + 2 x 2 1

x+1

x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

x +1 x > 1

= {

d. y - 1

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a.y =

x+1 x 21

C. y =

x + 1

x < 1

-x+ 2 x < 1

b.y = {

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d. y - 1

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x < 1{-x+ 2 x < 1 S-x + 2 x > 1

a.y =

x+1 x 21

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x + 1

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b.y = {

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a.y =

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I alwayse get confused with the fractions and the grouping symbols. can someone plz explain how to solve this kind of problem?​

I alwayse get confused with the fractions and the grouping symbols. can someone plz explain how to solve this kind of problem?