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The direction of the centripetal acceleration is towards Saturn
Explanation:
When an object moves in a circular motion, there must be a force that "pulls" the object towards the centre of the circle, keeping it in a circular motion. This force is called centripetal force.
As a consequence, due to the relationship between force and acceleration (Newton's second law), there is also an acceleration that points towards the centre: this acceleration is called centripetal acceleration.
The magnitude of the centripetal acceleration is given by:
where
m is the mass of the object
v is its speed
r is the radius of the circle
Therefore in this situation, the centripetal acceleration points towards the centre of the circle: therefore, towards Saturn, which occupies the centre of the circular trajectory.
Learn more about centripetal acceleration:
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It's a plain, not a lever
Answer:
even if it all could be used, it wouldn't be enough
Explanation:
The land area of the US is about 5.45% of the world's area, so the amount of released heat over the area of the US is on the order of 2.4 Tw. Current technology for converting geothermal energy to electricity is about 12% efficient, so the available energy might amount to 0.29 Tw if it could all be captured.
Energy consumption in the US in 2019 was on the order of 0.46 Tw. This suggests that even if <em>all</em> of the thermal energy radiated by the Earth from the US could be turned to useful forms of energy, it would meet only about 60% of the US need for energy.
Answer: a) 335.8 μm; b) keeping the same radius, the new has double potential, V=1340V so if teh radius is also double the potentail is the same (V=670V).
Explanation: In order to explain this problem we have to consider the potential given for sphere respect to infinity ( V=0) in the form:
V=k*Q/R the we have
R=k*Q/V= 9*10^9*25*10^-12/670=335.8 *10^-6 m
When two drop join to form a single drop (considering with the same radius) we have:
V=k*2Q/R
So the new V is double the original,
V=9*10^9*2*25*10^-12/335.8*10^-6=1340V
if the final single drop has a 2R of radius so
V=k*2Q/2R= 670 V
It has the same original potential.