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Vitek1552 [10]
3 years ago
14

Describe the quantum mechanical model of the atom and several observations which support this model.

Physics
1 answer:
PIT_PIT [208]3 years ago
7 0

This means that we shouldn't imagine electrons as single objects going around the atom. Instead, all we know is the probability of finding an electron at a particular location. What we end up with is something called an electron cloud. An electron cloud is an area of space in which an electron is likely to be found. It's like a 3-D graph showing the probability of finding the electron at each location in space. Quantum mechanics also tells us that a particle has certain numbers (called quantum numbers) that represent its properties. Just like how materials can be hard or soft, shiny or dull, particles have numbers to describe the properties. These include a particle's orbital quantum numbers, magnetic quantum number, and its spin. No two electrons in an atom can have exactly the same quantum numbers. Orbital quantum numbers tell you what energy level the electron is in. In the Bohr model, this represents how high the orbit is above the nucleus; higher orbits have more energy. The first orbit is n=1, the second is n=2, and so on. The magnetic quantum number is just a number that represents which direction the electron is pointing. The other important quantum mechanical property, called spin, is related to the fact that electrons come in pairs. In each pair, one electron spins one way (with a spin of one half), and the other electron spins the other way (with a spin of negative one half). Two electrons with the same spin cannot exist as a pair. This might seem kind of random, but it has effects in terms of how magnetic material is. Materials that have unpaired electrons are more likely to be magnetic

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A rocket is fired straight upward, starting from rest with an acceleration of 25.0 m/s^2. It runs out of fuel at the end of 4.00
ANTONII [103]

Answer:

a) 200m, 100m/s

b) 710.20m

c) -117.98 m/s

d) 26.24 s

Explanation:

To solve this  we have to use the formulas corresponding to a uniformly accelerated motion problem:

V=Vo+a*t (1)

X=Xo+Vo*t+\frac{1}{2}*a*t^2\\ (2)

V^2=Vo^2+2*a*X (3)

where:

Vo is initial velocity

Xo=intial position

V=final velocity

X=displacement

a)

X=0+0*4+\frac{1}{2}*25*4^2

the intial position is zero because is lauched from the ground and the intial velocitiy is zero because it started from rest.

X=200m

V=0+25*4

V=100m/s

b)

The intial velocity is 100m/s we know that because question (a) the acceleration is -9.8\frac{m}{s^2} because it is going downward.

0=100^2+2*(-9.8)*X\\X=510.20\\totalheight=200+510.20=710.20m

c)

In order to find the velocity when it crashes, we can use the formula (3).

the initial velocity is 0 because in that moment is starting to fall.

V^2=0^2+2*(-9.8)*(710.20)\\V=-117.98 m/s

the minus sign means that the object is going down.

d)

We can find the total amount of time adding the first 4 second and the time it takes to going down.

to calculate the time we can use the formula (2) setting the reference at 200m:

-200=0+100*t+\frac{1}{2}*(-9.8)*t^2

solving this we have: time taken= 22.24 seconds

total time is:

total=22.24+4=26.24 seconds.

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2 years ago
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