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Vitek1552 [10]
3 years ago
14

Describe the quantum mechanical model of the atom and several observations which support this model.

Physics
1 answer:
PIT_PIT [208]3 years ago
7 0

This means that we shouldn't imagine electrons as single objects going around the atom. Instead, all we know is the probability of finding an electron at a particular location. What we end up with is something called an electron cloud. An electron cloud is an area of space in which an electron is likely to be found. It's like a 3-D graph showing the probability of finding the electron at each location in space. Quantum mechanics also tells us that a particle has certain numbers (called quantum numbers) that represent its properties. Just like how materials can be hard or soft, shiny or dull, particles have numbers to describe the properties. These include a particle's orbital quantum numbers, magnetic quantum number, and its spin. No two electrons in an atom can have exactly the same quantum numbers. Orbital quantum numbers tell you what energy level the electron is in. In the Bohr model, this represents how high the orbit is above the nucleus; higher orbits have more energy. The first orbit is n=1, the second is n=2, and so on. The magnetic quantum number is just a number that represents which direction the electron is pointing. The other important quantum mechanical property, called spin, is related to the fact that electrons come in pairs. In each pair, one electron spins one way (with a spin of one half), and the other electron spins the other way (with a spin of negative one half). Two electrons with the same spin cannot exist as a pair. This might seem kind of random, but it has effects in terms of how magnetic material is. Materials that have unpaired electrons are more likely to be magnetic

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A 0.20-kg mass is oscillating on a spring over a horizontal frictionless surface. When it is at a displacement of 2.6 cm for equ
valentinak56 [21]

Explanation:

The given data is as follows.

                    mass = 0.20 kg

              displacement = 2.6 cm

              Kinetic energy = 1.4 J

       Spring potential energy = 2.2 J

Now, we will calculate the total energy present present as follows.

         Total energy = Kinetic energy + spring potential energy

                           = 1.4 J + 2.2 J

                            = 3.6 Joules

As maximum kinetic energy of the object will be equal to the total energy.

So,      K.E = Total energy

                = 3.6 J

Also, we know that

                  K.E = \frac{1}{2}mv^{2}_{m}

or,                   v = \sqrt{\frac{2K.E}{m}}

                        = \sqrt{2 \times 3.6 J}{0.2 kg}

                        = \sqrt{36}

                        = 6 m/s

thus, we can conclude that maximum speed of the mass during its oscillation is 6 m/s.

4 0
3 years ago
A 56-kg skater initially at rest throws a 5.0-kg medicine ball horizontally to the left. Suppose the ball is accelerated through
aniked [119]

Answer:

a_2=24.5\ \text{m/s}^2 towards right

a_1=2.1875\ \text{m/s}^2 towards left

Explanation:

m_1 = Mass of skater = 56 kg

m_2 = Mass of ball = 5 kg

v = Final velocity of ball = 7 m/s

u = Initial velocity of ball = 0

s = Distance the ball moved in the hand of the skater = 1 m

Moving left is considered and moving right is considered positive.

From kinematic equations of motion we have

v^2-u^2=2as\\\Rightarrow a=\dfrac{v^2-u^2}{2s}\\\Rightarrow a=\dfrac{7^2-0^2}{2\times 1}\\\Rightarrow a=24.5\ \text{m/s}^2

So, the ball will move towards right with a magnitude of acceleration a_2=24.5\ \text{m/s}^2.

The force on the ball will be

F_2=m_2a_2\\\Rightarrow F_2=5\times 24.5\\\Rightarrow F_2=122.5\ \text{N}

The force on the ball is 122.5\ \text{N}

The reaction force on the skater will be equal to the force on the ball but will have opposite direction.

-F_1=F_2\\\Rightarrow -m_1a_1=F_2\\\Rightarrow a_1=-\dfrac{122.5}{56}\\\Rightarrow a_1=-2.1875\ \text{m/s}^2

So, the skater will move towards left with a magnitude of acceleration 2.1875\ \text{m/s}^2

4 0
3 years ago
What can hold a greater volume of water than a mug
Volgvan
A jug would hold more volume than a mug
7 0
4 years ago
Read 2 more answers
Show that the expression pRT has the same units as the pressure, and thus that the ideal gas law is dimensionally consistent.
Gemiola [76]

Answer and Explanation:

We have given the expression \rho RT

Dimension of \rho =ML^{-3}

Dimension of R which is gas constant=ML^2T^{-2}\Theta ^{-1}M^{-1}

Dimension of temperature T \Theta ^{-1}

And dimension of pressure ML^{-1}T^{-2}

Now combine dimension of \rho RT =ML^{-3}ML^2T^{-2}\Theta ^{-1}M^{-1}\Theta ^{-1}=ML^{-1}T^{-2}

So the dimension of \rho RT  and dimension P is same so there unit will also be same

From ideal gas equation we know that PV=nRT

P=\frac{n}{V}RT=\rho RT

As the both P and  \rho RT  has same dimension so they are dimensionally constant

7 0
4 years ago
Suggest and explain two ways to reduce heat loss through the doors of the house.
emmainna [20.7K]
Keep the doors closed and make sure there isnt lots of open space between the door and the frame
8 0
4 years ago
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