Question

I'm not sure what to use help me please

Answer 1

Answer:

Mass of the ring is 2.5 kg.

Given:

Moment of inertia of a ring = 0.4 kg.$m^{2}$

Radius = 40 cm = 0.4 m

To find:

Mass of the ring = ?

Formula used:

I = m $r^{2}$

Where I = moment of inertia

r = radius of the ring

m = mass of the ring

Solution:

Moment of inertia of a ring is given by,

I = m $r^{2}$

Where I = moment of inertia

r = radius of the ring

m = mass of the ring

0.4 = m ×0.4×0.4

m = 0.4/(0.4×0.4)

m = 1/0.4

m = 2.5 kg

Mass of the ring is 2.5 kg.