I'm not sure what to use help me please
1 answer:
Answer:
Mass of the ring is 2.5 kg.
Given:
Moment of inertia of a ring = 0.4 kg.
Radius = 40 cm = 0.4 m
To find:
Mass of the ring = ?
Formula used:
I = m
Where I = moment of inertia
r = radius of the ring
m = mass of the ring
Solution:
Moment of inertia of a ring is given by,
I = m
Where I = moment of inertia
r = radius of the ring
m = mass of the ring
0.4 = m ×0.4×0.4
m = 0.4/(0.4×0.4)
m = 1/0.4
m = 2.5 kg
Mass of the ring is 2.5 kg.
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Answer: 585 J
Explanation:
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where Kf is the final kinetic energy and Ki the initial kinetic energy. The initial kinetic energy is zero (because the initial velocity is 0), while the final kinetic energy is
The mass is m=1.3 kg, while the final velocity is v=30 m/s, so the work done is:
Answer: f=150cm in water and f=60cm in air.
Explanation: Focal length is a measurement of how strong light is converged or diverged by a system. To find the variable, it can be used the formula:
= (nglass - ni)(
-
).
nglass is the index of refraction of the glass;
ni is the index of refraction of the medium you want, water in this case;
R1 is the curvature through which light enters the lens;
R2 is the curvature of the surface which it exits the lens;
Substituting and calculating for water (nwater = 1.3):
= (1.5 - 1.3)(
-
)
= 0.2(
)
f = = 150
For air (nair = 1):
= (1.5 - 1)(
-
)
f = = 60
In water, the focal length of the lens is f = 150cm.
In air, f = 60cm.