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alexgriva [62]
3 years ago
8

I'm not sure what to use help me please

Physics
1 answer:
DaniilM [7]3 years ago
5 0

Answer:

Mass of the ring is 2.5 kg.

Given:

Moment of inertia of a ring = 0.4 kg.m^{2}

Radius = 40 cm = 0.4 m

To find:

Mass of the ring = ?

Formula used:

I = m r^{2}

Where I = moment of inertia

r = radius of the ring

m = mass of the ring

Solution:

Moment of inertia of a ring is given by,

I = m r^{2}

Where I = moment of inertia

r = radius of the ring

m = mass of the ring

0.4 = m ×0.4×0.4

m = 0.4/(0.4×0.4)

m = 1/0.4

m = 2.5 kg

Mass of the ring is 2.5 kg.

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mestny [16]

Answer:bsnz

Explanation:nslsosols

7 0
2 years ago
You're driving down the highway late one night at 20 m/s when a deer steps onto the road 44 m in front of you. Your reaction tim
never [62]

Answer:

14.0 m

25.1 m/s

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

Distance traveled in the reaction time

Distance = Speed × Time

\text{Distance}=20\times 0.5=10\ m

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{0^2-20^2}{2\times -10}\\\Rightarrow s=20\ m

Distance in which the car will stop is 10+20 = 30.0 m

So, the car will not hit the deer

Distance between the car and deer is 44-30 = 14.0 m

\text{Distance}=u\times 0.5=0.5u\ m

v^2-u^2=2as\\\Rightarrow -u^2=2as-v^2\\\Rightarrow u^2=v^2-2as\\\Rightarrow u^2=0^2-2\times -10\times (44-0.5u)\\\Rightarrow u^2=20(44-0.5u)\\\Rightarrow u^2=880-10u\\\Rightarrow u^2+10u-880=0

u=\frac{-10+\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}, u=\frac{-10-\sqrt{10^2-4\cdot \:1\left(-880\right)}}{2\cdot \:1}\\\Rightarrow u=25.08, -35.08\ m/s

Maximum speed of the car by which it will not hit the deer is 25.1 m/s

5 0
3 years ago
Read 2 more answers
A power source of 2.0 V is attached to the ends of a capacitor. The capacitance is 4.0 μF.
Aleksandr-060686 [28]
Answer:
Q = 8 μC

Explanation:
The relation between voltage, capacitance and charge can be expressed using the following rule:
Q = C * V
where:
Q is the amount of charge that we want to calculate
C is the capacitance = 4 * 10⁻⁶ F
V is the voltage applied = 2 V

Substitute with the givens in the above equation to get the amount of charge as follows:
Q = C * V
Q= 4 * 10⁻⁶ * 2
Q = 8 * 10⁻⁶ Coulumb
Q = 8 μC

Hope this helps :)
7 0
3 years ago
Read 2 more answers
Which of the following choices is an accurate example of how the use of cultural tools is important in the development of one’s
kifflom [539]

the correct answer is c according to ed genuity

5 0
3 years ago
Read 2 more answers
A spring with k = 19.5 N/cm is initially stretched 1.39 cm from its equilibrium length. a) How much more energy is needed to fur
lara31 [8.8K]

Answer:

Energy needed = 54.02 J

Explanation:

the Energy in an elastic spring from hookes law is given  as

F= ke , therefore the energy (E) is

E = \frac{1}{2} Ke^{2}

K = 19.5 N/cm

e = 1.39cm

E = \frac{1}{2} x 19.5 x 1.39

E = 13.55 J

The energy to stretch the spring for 6.93cm is

E = \frac{1}{2} x 19.5 x 6.93

E = 67.57 J

The more energy needed for the further stretch is

67.57 - 13.55

Energy needed = 54.02 J

7 0
3 years ago
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