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kifflom [539]
3 years ago
6

A chemical reaction in a lab experiment actually produces 1.23mol of BeBr2. The theoretical yield is 220g. To two decimal places

, what is the percentage yield
Chemistry
1 answer:
Mashutka [201]3 years ago
5 0

Answer:

Percent yield = 94.62%

Explanation:

Given data:

Actual yield of BeBr₂ = 1.23 mol

Theoretical yield of BeBr₂ = 220 g

Percent yield = ?

Solution:

Theoretical yield in moles:

Number of moles = mass/molar mass

Number of moles = 220 g/168.82 g/mol

Number of moles = 1.30 mol

Percent yield:

Percent tiled = actual yield / theoretical yield × 100

by putting values,

Percent yield = 1.23 mol / 1.30 mol × 100

Percent yield = 0.9462 × 100

Percent yield = 94.62%

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Rubber is not very good at conducting electricity. This is because rubber makes it difficult for electrons to flow between atoms, due to rubber having tightly packed electrons. Materials like rubber are known as insulators.
Conductors are the opposite, they conduct electricity very well. Examples of conductors are metal, which is why metal is used in wires.
Since rubber is not a conductor, answer choice B can be eliminated. This can also eliminate answer choice D, since insulators like rubber don't allow electricity to easily flow.
While rubber gloves keep our hands dry, there are no liquids involved in this experiment and this is not the main reason for using rubber gloves. This eliminates answer choice C.

The answer is A. rubber gloves are insulators.
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Answer:
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Hope this helps!
5 0
3 years ago
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Which type of bond is present within a water molecule
krok68 [10]

Answer:

Covalent bonds

Explanation:

3 0
3 years ago
A gas of unknown molecular mass was allowed to effuse through a small opening under constant-pressure conditions. It required 10
masya89 [10]

<u>Answer:</u> The molar mass of unknown gas is 367.12 g/mol

<u>Explanation:</u>

Rate of a gas is defined as the amount of gas displaced in a given amount of time.

\text{Rate}=\frac{V}{t}

To calculate the rate of diffusion of gas, we use Graham's Law.

This law states that the rate of effusion or diffusion of gas is inversely proportional to the square root of the molar mass of the gas. The equation given by this law follows the equation:

\text{Rate of effusion}\propto \frac{1}{\sqrt{\text{Molar mass of the gas}}}

So,

\left(\frac{\frac{V_{X}}{t_{X}}}{\frac{V_{O_2}}{t_{O_2}}}\right)=\sqrt{\frac{M_{O_2}}{M_{X}}}

We are given:

Volume of unknown gas (X) = 1.0 L

Volume of oxygen gas = 1.0 L

Time taken by unknown gas (X) = 105 seconds

Time taken by oxygen gas = 31 seconds

Molar mass of oxygen gas = 32 g/mol

Molar mass of unknown gas (X) = ? g/mol

Putting values in above equation, we get:

\left(\frac{\frac{1.0}{105}}{\frac{1.0}{31}}\right)=\sqrt{\frac{32}{M_X}}\\\\M_X=367.12g/mol

Hence, the molar mass of unknown gas is 367.12 g/mol

3 0
4 years ago
2-- What is the [H3O+] in a solution with [OH-] = 1 x 10-12 M?<br>​
Arte-miy333 [17]

Answer:

The answer is 0.01 M

Explanation:

The problem is solved by applying the expression for ionic product of water as follows:

Kw = [H₃O⁺] [OH⁻]

Where Kw is the ionic product of water and it is 1.10⁻¹⁴ M at⁴ 25ºC. As [OH⁻]= 1.10⁻¹² M, [H₃O⁺] will be:

[H₃O⁺]= Kw/ [OH⁻]= 1.10⁻¹⁴M/1.10⁻¹²M= 0.01 M

5 0
3 years ago
Question 1<br> Review<br> Which laboratory equipment is correctly paired with the unit it measures?
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Answer:

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6 0
3 years ago
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