The mass of iron (III) oxide (Fe2O3) : 85.12 g
<h3>Further explanation</h3>
Given
3.20x10²³ formula units
Required
The mass
Solution
1 mole = 6.02.10²³ particles
Can be formulated :
N = n x No
N = number of particles
n = mol
No = 6.02.10²³ = Avogadro's number
mol of Fe₂O₃ :
mass of Fe₂O₃ (MW=160 g/mol)
Answer:
★ v = d/t
★ v = 90/30
★ v =3
<u>Acc</u><u> </u><u>to</u><u> </u><u>question</u>
★ momentum = mass * velocity
★ m = 25×3
★ m = 75kgm/s
Hope it help
a. 35.8 KJ
b. 871 g
c. Fe
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