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ololo11 [35]
3 years ago
9

2-- What is the [H3O+] in a solution with [OH-] = 1 x 10-12 M?​

Chemistry
1 answer:
Arte-miy333 [17]3 years ago
5 0

Answer:

The answer is 0.01 M

Explanation:

The problem is solved by applying the expression for ionic product of water as follows:

Kw = [H₃O⁺] [OH⁻]

Where Kw is the ionic product of water and it is 1.10⁻¹⁴ M at⁴ 25ºC. As [OH⁻]= 1.10⁻¹² M, [H₃O⁺] will be:

[H₃O⁺]= Kw/ [OH⁻]= 1.10⁻¹⁴M/1.10⁻¹²M= 0.01 M

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Would you expect Nio to dissolve in an aqueous solution of NaNO3?
Doss [256]

Answer:

NiO Does Not Dissolve In An Aqueous Solution Of NaNO3.

Explanation:

6 0
2 years ago
your science teacher hands you a small container filled with an unknown liquid substance. he asks you to measure the mass of the
koban [17]
 we are asked in this problem to determine the mass of a liquid in a small container. In order to determine the mass, we use an analytical balance for greater accuracy by first weighing the whole system (liquid+beaker). Then transfer the liquid to another container and completely dry the beaker (wash and dry). measure the weight of the beaker. The mass of the liquid is equal to the mass of the system minus the mass of the beaker. 
8 0
2 years ago
Which of the subshells below do not exist due to the constraints upon the angular momentum quantum number?A) 2dB) 2sC) 2pD) all
Gnom [1K]

Answer:

  • Option A): <em>Due to the constraints upton the angular momentum quantum number, the subshell </em><u><em>2d</em></u><em> does not exist.</em>

Explanation:

The <em>angular momentum quantum number</em>, identified with the letter l (lowercase L),  number is the second quantum number.

This number identifies the shape of the orbital or <em>kind of subshell</em>.

The possible values of the angular momentum quantum number, l, are constrained by the value of the principal quantum number n: l can take values from 0 to n - 1.

So, you can use this guide:

Principal quantum   Angular momentum         Shape of the orbital

number, n                 quantum number, l

         1                                      0                             s

         2                                     0, 1                          s, p

         3                                     0, 1, 2                      s, p, d

Hence,

  • <u>the subshell 2d (n = 2, l = 2) is not feasible</u>.

  • 2s (option B) is possible: n = 2, l = 0

  • 2p (option C) is possible: n = 2, l = 1

7 0
3 years ago
Consider the following ionic compounds: CdCO3, Na2S, PbSO4, (NH4)3PO4, and Hg2Cl2. Which compounds will be soluble when added to
Grace [21]

Answer:

a. Na₂S and (NH₄)₃PO₄ .

Explanation:

To know which salts are soluble we need to remember some <em>solubility rules</em>. And apply these as follows:

* All compounds of group 1 (Li⁺, Na⁺, K⁺, etc.) are soluble, Na₂S is soluble.

* All ammonium salts are soluble,

<h3>(NH₄)₃PO₄ is soluble.</h3>

* All Cl⁻, I⁻, Br⁻ are soluble except when are with Ag⁺, Hg₂²⁺, Pb²⁺, Hg₂Cl₂ is <em>insoluble</em>

* Carbonates are insoluble except those with group 1 or ammonium, CdCO₃ is <em>insoluble</em>

* All sulfates are soluble except those with Ca²⁺, Sr²⁺, Ba²⁺, Pb²⁺, Ag⁺. PbSO₄ is <em>insoluble. </em>

Right solution is:

<h3>a. Na₂S and (NH₄)₃PO₄ </h3>

8 0
3 years ago
8.03 Lab Report Data Answers (I only need the Data as I do not have the time to get the materials and do it myself but I don't n
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Answer:

subject?

Explanation:

7 0
3 years ago
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