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3 years ago

Question 1 Review Which laboratory equipment is correctly paired with the unit it measures?

Chemistry

1 answer:

Bad White [126]3 years ago

6 0

Answer:

Cilindros graduados

Explanation:

Son una herramienta de medición primaria para el volumen de un líquido, y tiene varias marcas hacia arriba y hacia abajo a lo largo del contenedor con incrementos específicos. Los cilindros graduados vienen en muchos tamaños; entre más pequeños sean de diámetro, más específicas serán las mediciones de volumen. Al leer el volumen de un cilindro graduado, notarán que el líquido parece tener una muesca; el líquido alrededor de los bordes será más alto que el líquido en el centro, inclinándose hacia abajo como los lados de un trampolín cuando alguien está parado en el medio. Esto se llama el menisco. Alineen el punto más bajo del menisco con la marca más cercana, manteniendo el nivel del cilindro para leer correctamente el volumen.

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QUESTION 8

Alona [7]

1. combustion
2.decompostioni
3.synthesids
4double replacement
5.single replacement

8 0

3 years ago

How many atoms of lead are contained in 0.532mol?

Colt1911 [192]

Answer:

3.2043 x 10²³

Explanation:

No. of Mole of lead (Pb) = 0.532 mol

No. of atoms of lead = ?

Solution:

Formula Used to calculate

no. of moles = numbers of particles (ions, molecules, atoms) /Avogadro's number

Avogadro's no. = 6.023 x10²³

So,

The formula could be written as

no. of atoms of lead Pb = no. of moles x 6.023 x10²³

Put the values in above formula

no. of atoms of lead Pb = 0.532 mol x 6.023 x10²³

no. of atoms of lead Pb = 3.2043 x 10²³

so 3.2043 x 10²³ atoms of lead are contained in 0.532 mole.

6 0

3 years ago

A 30-0 g sample of water at 280 K is mixed with 50.0 g of water at 330 K. How would you calculate the final temperature of the m

aliya0001 [1]

Answer:

311.25k

Explanation:

The question assumes heat is not lost to the surroundings, therefore

heat emitted from hotter sample ( $q_{\ lost}$ )= heat absorbed by the less hotter sample( $q_{\ gain}$ )

The relationship between heat (q), mass (m) and temperature (t) is $q = mc\Delta t$

where c is specific heat capacity, $\Delta t$ temperature change.

$\Delta t$ = $t_{\ final} - t_{\ initial}$

equating both heat emitted and absorb

$-q_{\ lost} = q_{\ gain}$

$-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})$

where the values with subset 1 are the values of the hotter sample of water and the values with subset 2 are the values of the less hot sample of water.

C will cancel out since both are water and they have the same specific heat capacity.

so we have

$-m_{1}(t_{\ final} - t_{\ 1initial})=m_{2}(t_{\ final} - t_{\ 2initial})$

where m1 = 50g, t 1initial = 330, m2 = 30g, t2 initial = 280,t final (final temperature of the mixture) = ?

-50 * ( $t_{final}$ - 330) = 30 * ( $t_{final}$ - 280)

-50 $t_{final}$ + 16500 = 30 $t_{final}$ - 8400

80 $t_{final}$ = 16500+8400

80 $t_{final}$ = 24900

$t_{final}$ = 24900/80 = 311.25k

8 0

3 years ago

Be sure to explain each step in the energy flow, identifying the form of energy represented and how it changes from one form to

Dvinal [7]

The question that you asked has already been answered

5 0

3 years ago

The molar heat of fusion of gold is 12. 550 kJ mol–1. At its melting point, how much mass of melted gold must solidify to releas

wlad13 [49]

Answer:

plyojexity

Explanation:

222^ -67'h~=H87

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3 years ago