3 years ago

The weight of an object is the force pulling the object:

Physics

1 answer:

oksano4ka [1.4K]3 years ago

6 0

D pulling because of gravity

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A spring that is compressed 14.5 cm from its equilibrium position stores 2.99 J of potential energy. Determine the spring consta

strojnjashka [21]

Answer:

284.4233 N/m

Explanation:

k = Spring constant

x = Compression of spring = 14.5 cm

U = Potential energy = 2.99 J

The potential energy of a spring is given by

$U=\dfrac{1}{2}kx^2$

Rearranging to get the value of k

$\\\Rightarrow k=\dfrac{2U}{x^2}\\\Rightarrow k=\dfrac{2\times 2.99}{0.145^2}\\\Rightarrow k=284.4233\ N/m$

The spring constant is 284.4233 N/m

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3 years ago

(4.3 x 10-2 )4.950 x 105)<br> O 21.285 x 103<br> O 2.13 x 104<br> O 21 x 103<br> O 2.1 x 104

Natalka [10]

Answer:

The answer is:

It's 21.285 × 103

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2 years ago

The angle between the axes of two polarizing filters is 45.0^\circ45.0 ∘ . By how much does the second filter reduce the int

suter [353]

Answer

given,

angle between two polarizing filters = 45°

filter reduce intensity = ?

a) I = I₀ Cos² θ

here θ = 45⁰

$I = \dfrac{I_0}{2}$

intensity of the light is reduced by 0.500

correct answer from the given option D

b) direction of the polarization

θ = 45°

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3 years ago

Krishne wants to measure the mass and volume of a key. Which tools should she use? a balance and a beaker of water a balance and

Ratling [72]

Balance and beaker of water. The balance will measure mass and the beaker will measure the volume when you take the initial volume without the key subtracting that value from the value with the key in the beaker

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3 years ago

Read 2 more answers

si un disco fue lanzado con una fuerza de 1000 N, y el disc recorrió una distancia e o.6 m ¿Qué trabajo efectuó el lanzador ?

Alexeev081 [22]

Answer:

Trabajo realizado = 600 Nm

Explanation:

Dados los siguientes datos;

Fuerza = 1000 Newton

Distancia = 0.6 metros

Para encontrar el trabajo realizado;

$Trabajo \; realizado = fuerza * distancia$

Sustituyendo en la ecuación, tenemos;

$Trabajo \; realizado = 1000 * 0.6$

Trabajo realizado = 600 Nm

4 0

2 years ago