Answer:
Final temperature of the aluminum = 41.8 °C
Explanation:
We have the equation for energy
E = mcΔT
Here m = 55 g = 0.055 kg
ΔT = T - 27.5
Specific heat capacity of aluminum = 921.096 J/kg.K
E = 725 J
Substituting
E = mcΔT
725 = 0.055 x 921.096 x (T - 27.5)
T - 27.5 = 14.31
T = 41.81 ° C = 41.8 °C
Final temperature of the aluminum = 41.8 °C
Answer:
1793.7m
Explanation:
From the principle of conservation of energy; the kinetic energy substended by the object equals the potential energy sustain by the object when it gets to its maximum position.
Now the kinetic energy; is
K.E = 1/2 × m × v2
Where m is mass
v is velocity
Hence.
K.E = 1/2 × 2.25 × (187.5)^2
Now this should be same with the potential energy which is given as;
P.E = m× g× h
Where m is mass of object
g is acceleration of free fall due to gravity = 9.8m/S2
h is maximum height substain by the object.
Hence P.E = 2.25 × 9.8 × h
From the foregoing analysis of energy conversation it implies;
1/2 × 2.25 × (187.5)^2 =2.25 × 9.8 × h
=> 1/2 × (187.5)^2 = 9.8 × h
=>1/2 × (187.5)^2 / 9.8 = h
=> 1793.69m = h
h= 1793.69m
h =1793.7m to 1 decimal place
Answer:what is the question exactly
Explanation:
Answer:
The average power of the engine of the sports car is 56.32 kW
Explanation:
Given;
mass of the sports car, m = 1100 kg
initial velocity of the sports car, u = 0 m/s
final velocity of the sports car, v = 32 m/s
time of motion, t = 10 s
The kinetic energy of the car is given by;
K.E = ¹/₂m(v² - u²)
K.E = ¹/₂mv²
K.E = ¹/₂ x 1100 x 32²
K.E = 563200 J
The average power of the engine of the sports car is given by;
Pavg = Energy / time
Pavg = 563200 / 10
Pavg = 56320 W
Pavg = 56.32 kW
Therefore, the average power of the engine of the sports car is 56.32 kW
Answer:
D.300nm
Explanation:
Wavelength = Speed of light / Frequency of light.....
where the speed of light is...(3 × 10^8)
Wavelength = (3 × 10^8)/(1 × 10^15)
Wavelength = 3 × 10^-7
;Wavelength = 300 × 10^-9
Hence its....300 nm
