The peak magnetic field of the electromagnetic wave in the red part of the visible spectrum is 9.67 x 10⁻¹⁰ T.
<h3>Relationship between electric and magnetic field</h3>
The relationship between electric and magnetic field at a given peak electric field is given as;
c = (E₀) / (B₀)
where;
- c is speed of light
- E₀ is the peak electric field
- B₀ is the peak magnetic field
B₀ = E₀ / c
B₀ = (2.9) / (3 x 10⁹)
B₀ = 9.67 x 10⁻¹⁰ T
Thus, the peak magnetic field of the electromagnetic wave in the red part of the visible spectrum is 9.67 x 10⁻¹⁰ T.
Learn more about peak magnetic field here: brainly.com/question/24487261
Answer:
F(Mars) = 2 G m M / (4 R)^2 force of Sun on Mars
F(Merc) = G m M / R^2 force of force of Sun on Mercury
R = distance of Sun from Mercury, m = mass of Mercury
F(Merc) / F(Mars) = 4^2 / 2 = 8
Yes it is valid all the times under the consideration of acceleration due to gravity .it is not valid on space where there is no influence of gravity
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