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Lina20 [59]
3 years ago
10

You are standing on a scale in an elevator. suddenly you notice your weight decreases. what do you conclude? a. the elevator is

accelerating downwards. b. the elevator is accelerating upwards. c. the elevator is moving at a constant velocity upwards. d. your diet is working. e. the elevator is moving at a constant velocity downwards.
Physics
1 answer:
solong [7]3 years ago
3 0

Answer:

The elevator is accelerating downwards.

Explanation:

When an elevator accelerating downward it moves together with the person inside and the weight of the person does not change, but if the person is standing on a scale the contact force between the person and the scale is reduced.  The scale therefore has to push upward with less force on the person to support the person's weight. Therefore the Normal Force is smaller, so the reading on the scale becomes less than the true weight.

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Which of the following is not a requirement of a practical fuel? A. It must occur in abundance in nature or be easy to produce.
Masteriza [31]

Answer: Option D: It must be in the solid state to be used.

A material that is used to provide energy is for work is known as fuel. For practical use, it is important that the fuel must occur in abundance or can be easily produced. It should be made of elements that can easily combine with oxygen. This is required for burning. It must produce large amount of energy. So, it must contain large amount of stored energy. It is useful only when a small quantity can produce large amount of energy. It can be in any state, solid liquid or gas.

Therefore, it is not important that it must be in the solid state to be used.

7 0
3 years ago
Suppose you exert a force of 180 N tangential to a 0.280-m-radius 75.0-kg grindstone (a solid disk). What is the angular acceler
Lina20 [59]

Explanation:

It is given that,

Force on grindstone, F = 180 N

Radius of grindstone, r = 0.28 m

Mass of grindstone, m = 75 kg

We need to find the angular acceleration of the grindstone. In rotational motion, the relation between the torque and angular acceleration is given by :

\tau=I\times \alpha

\alpha=\dfrac{\tau}{I}

I is the moment of inertia of solid disk, I=\dfrac{1}{2}mr^2

\tau is the torque exerted, \tau=F\times r

\alpha=\dfrac{F\times r}{\dfrac{1}{2}mr^2}

\alpha=\dfrac{2F}{mr}

\alpha=\dfrac{2\times 180\ N}{75\ kg\times 0.28\ m}

\alpha =17.14\ rad/s^2

So, the angular acceleration of the disk is 17.14\ rad/s^2. Hence, this is the required solution.

5 0
3 years ago
According to Kepler's third law (p2 = a3), how does a planet's mass affect its orbit around the Sun? Group of answer choices
anyanavicka [17]

Answer:

A planet's mass has no effect on its orbit around the Sun.

Explanation:

The kepler's third law tells us:

p^2=a^3

where p is the orbit period and a is the semi-major axis.

As we can see from the equation, the period depends only on the measure of the semi-major axis a of the orbit, that is, how far a planet is from the sun.

The equation tells us that the closer a planet is to the sun, the faster it will go around it.

The mass does not appear in the equation to calculate the period.

This is why it is concluded from the third law of Kepler that<u> the period, or the orbit of a planet around the sun, does not depend on its mass.</u>

the answer i: A planet's mass has no effect on its orbit around the Sun.

3 0
3 years ago
This is Formation of the Solar System Lab Report
Ainat [17]

Answer:

the answer is B it is right

Explanation:

3 0
2 years ago
A diver rises quickly to the surface from a 5.0 m depth. If she did not exhale the gas from her lunds before rising, by what fac
Inessa [10]

Answer:

1.5 times

Explanation:

h = depth of the diver initially = 5 m

\rho = density of seawater = 1030 kg m⁻³

P_{i} = Initial pressure at the depth

P_{f} = final pressure after rising = 101325 Pa

Initial pressure at the depth is given as

P_{i} = P_{f} + \rho gh\\P_{i} = 101325 + (1030) (9.8) (5)\\P_{i} = 151795 Pa

V_{i} = Initial volume at the depth

V_{f} = Final volume after rising

Since the temperature remains constant, we have

P_{f} V_{f} = P_{i} V_{i}\\(101325) V_{f} = (151795) V_{i}\\V_{f} = 1.5 V_{i}

6 0
3 years ago
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