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labwork [276]
4 years ago
13

Describe the properties of metals, non-metals, and metalloids

Physics
1 answer:
VashaNatasha [74]4 years ago
3 0
<span><span>Metals are generally shiny, malleable, and hard. Metals are also good conductors of electricity. Examples of metals are Gold, Silver, Iron, Uranium, and Zinc. </span><span>Non-metals do not conduct heat or electricity very well. Non-metals are typically brittle and are not easily molded into shapes. Example non-metal elements are Hydrogen and Carbon. </span><span>Metalloids share characteristics of both metals and non-metals and are also called semimetals. Metalloids are typically semi-conductors, which means that they both insulate and conduct electricity. This semi-conducting property makes Metalloids very useful as a computer chip material. Examples of metalloid elements are Silicon and Boron. </span></span>
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1. A sample consisting of 1.0 mol CaCO3 (s) was heated to 800oC when it is decomposed. The heating was carried out in a containe
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During a 980. miles cruise, a ship travelled 590 miles in 7 hours first. Then the ship changed its speed for the rest of the tri
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Explanation:

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3 years ago
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You are working out on a rowing machine. Each time you pull the rowing bar (which simulates the "oars") toward you, it moves a d
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Answer:

54.67 N

Explanation:

The total energy produced is the product of power and time duration:

E = Pt = 82 * 1 = 82 J

Which is converted from work, product of forced extended over a displacement

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So the magnitude of the force exerting on the handle is 54.67 N

8 0
4 years ago
Write a linear equation that expresses the relationship between the temperature in degrees Celsius (C) and degrees Fahrenheit (F
UkoKoshka [18]

Answer:

\displaystyle F=\frac{9}{5}C+32

\displaystyle C=\frac{5}{9}(F-32)

Explanation:

<u>Temperature Units Conversion </u>

The conversion formula between Celsius and Fahrenheit temperature scales is well-known. But we'll use the provided data to derive the formula. Let's model the relationship between Fahrenheit (F) and Celsius (C) as a linear function like

F=mC+b

Where m and b must be computed according to the pair of conditions given. The values for each temperature scale are (C,F)=(0,32) and (100,212). Replacing the first value

32=m\times 0+b

It means that  

b=32

By using the second point

212=m\times 100+32

Solving for m

\displaystyle m=\frac{212-32}{100}=\frac{180}{100}

Simplifying

\displaystyle m=\frac{9}{5}

So, the conversion formula is

\displaystyle F=\frac{9}{5}C+32

Which is the widely known formula for temperature conversion

Solving for C, we get the inverse relation

\boxed{\displaystyle C=\frac{5}{9}(F-32)}

3 0
4 years ago
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