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lianna [129]
3 years ago
5

Which ratios are equivalent to 7/3? Check all that apply.

Mathematics
1 answer:
liq [111]3 years ago
5 0

Answer:

the answers are

2. 28 to 12

3.56 / 24

4. 63 to 27

2,3,4 are the answers.

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Pls help me with this question
Sedbober [7]

7/12,  3/4,  4/7,  5/8,  4/7

Answer:  

Order from Least to Greatest

4/7    =       4/7     <       7/12    <    5/8   <   3/4  

Showing Work  

Rewriting as fractions if necessary:  

7/12, 3/4, 4/7, 5/8, 4/7  

The least common denominator (LCD) is: 168.  

Rewriting as equivalent fractions with the LCD:  

98/168, 126/168, 96/168, 105/168, 96/168  

Ordering these fractions by the numerator in order from least to greatest:  

96/168    =    96/168     <     98/168    < 105/168    < 126/168  

Therefore, your input in order from least to greatest is:

Answer   =======>   4/7    =   4/7    <    7/12    <     5/8    < 3/4


B):  1.35,   5/4,   1.349,  6/5, 7/6

Number of inputs ====>  5

Answer => Ascending Order:  Least to Greatest =====>  7/6, 6/5, 5/4, 1.349, 1.35



C):   0.819,  0.8199, 81/100, 815/1000

Number of Inputs  ======>    4

Answer  ==> Ascending order (Least to Greatest ====>    81/100, 815/1000, 0.819, 0.8199



D):    3  4/7, 245/70, 3.572, 90/29

Number of Inputs:  4

Answer ==>  Ascending Order(Least to Greatest) ==> 90/29, 245/70, 3.572, 3 4/7




Hope that helps!!!!                                              : )

     


3 0
3 years ago
Read 2 more answers
Simplify the expression c+5+10
Darina [25.2K]

Answer:

c+15

Step-by-step explanation:

add the numbers c+15

c+15 is your answer.

5 0
3 years ago
Which description represents the expression 4 - r/3
sergey [27]
Hello,


The answer to this problem is, C.

4 minus the quotient of a number and 3



Hope this helps!
8 0
3 years ago
Find a and b such that gcd(a, b) = 14, a &gt; 2000, b &gt; 2000, and the only prime divisors of a and b are 2 and 7.
choli [55]

Answer:

a = 2^\alpha.14 \ ,\alpha\geq 8\\b = 7^\delta.14 \ , \delta\geq 3

Step-by-step explanation:

As 2  and 7 are the only prime divisors of both a and b we know that both can be written as:

a = 2^\alpha . 7^\beta \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Where \mathbb{N}_{0} is the set of all natural numbers adding the zero (careful because this part is important as I'll explain next).

We also know that 14 divides both numbers and that is actually the greatest common divisor between them. So we can rewrite a and b as follows:

a = 2^\alpha . 7^\beta.14 \ , \alpha ,\beta\ \in \mathbb{N}_{0}\\b = 2^\gamma . 7^\delta.14 \ , \gamma ,\delta\ \in \mathbb{N}_{0}\\

Why do I write them like this? Because this way is easier to observe that if \alpha and \gamma were both greater than zero, then 28 would divide both hence 14 wouldn't be their g.c.d.. Likewise, if \beta and \delta were both greater than zero, then 98 would divide both and once again, 14 wouldn't be their g.c.d.

So either of them has to be equal to zero. And then we have that

a = 2^\alpha.14 \\b = 7^\delta.14

All we have left to do is find the possible values for \alpha and \delta so that a>2000 \ , b>2000 and that only happens if \alpha\geq 8 and \delta\geq 3

8 0
3 years ago
What is the answer if you substitute 74 for y 74=x-1
klio [65]

Answer:

x=75

Step-by-step explanation:

74 = x-1

+1      +1

75=x

8 0
3 years ago
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