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OlgaM077 [116]
3 years ago
10

Express the ratio 5:35 in the form 1:n

Mathematics
2 answers:
Vsevolod [243]3 years ago
6 0

Answer:

answer is 7

Hope it's help you ❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️❤️

bearhunter [10]3 years ago
5 0
N=7 that is your answer
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If the three angles of a quadrilateral are 120, 130, 100 then what is the fourth angle?
nalin [4]

Answer:

c. 40

Step-by-step explanation:

3 0
3 years ago
Which expression gives the distance between the points (5, 1) and (9,-6)?
8_murik_8 [283]

9514 1404 393

Answer:

  C.  √((5-9)² +(1+6)²)

Step-by-step explanation:

The distance formula can be written ...

  d = √((x1 -x2)² +(y1 -y2)²)

Filling in the given point coordinates, this becomes ...

  d = √((5 -9)² +(1 -(-6))²)

Simplifying the signs, this becomes ...

  d = √((5 -9)² +(1 +6)²) . . . . . matches choice C

8 0
3 years ago
Use matrices and elementary row to solve the following system:
LiRa [457]

I assume the first equation is supposed to be

5x-3y+2z=13

and not

5x-3x+2x=4x=13

As an augmented matrix, this system is given by

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\4&-2&4&12\end{array}\right]

Multiply through row 3 by 1/2:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\2&-1&2&6\end{array}\right]

Add -1(row 2) to row 3:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&5&5\end{array}\right]

Multiply through row 3 by 1/5:

\left[\begin{array}{ccc|c}5&-3&2&13\\2&-1&-3&1\\0&0&1&1\end{array}\right]

Add -2(row 3) to row 1, and add 3(row 3) to row 2:

\left[\begin{array}{ccc|c}5&-3&0&11\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -3(row 2) to row 1:

\left[\begin{array}{ccc|c}-1&0&0&-1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Multiply through row 1 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\2&-1&0&4\\0&0&1&1\end{array}\right]

Add -2(row 1) to row 2:

\left[\begin{array}{ccc|c}1&0&0&1\\0&-1&0&2\\0&0&1&1\end{array}\right]

Multipy through row 2 by -1:

\left[\begin{array}{ccc|c}1&0&0&1\\0&1&0&-2\\0&0&1&1\end{array}\right]

The solution to the system is then

\boxed{x=1,y=-2,z=1}

5 0
3 years ago
Sue a tollbooth worker is paid $12.50 per hour between 8 Am and 4 pm. After 4 pm she is paid $14.25 per hour. If Sue works from
katrin2010 [14]

Answer:

She earns that day $103.5

Step-by-step explanation:

Lets explain how to solve the question

- She is paid $12.50 per hour between 8 am and 4 pm

- After 4 pm she is paid $14.25 per hour

- She works one particular day from 10 am to 6 pm

* Lets distribute her time of work into two part according to her

 payment above

# 1st part from 10 am to 4 pm

∵ She is paid $12.50 per hour between 8 am to 4 pm

∵ She works from 10 am to 4 pm

- Calculate how many hours between 10 am and 4 pm

∵ am and pm not like terms in time, so change the time to 24-hours

∵ 4 pm in 24-hour time is 4 + 12 = 16

∴ She works form 10 to 16

∴ She works for 6 hours (16  - 10 = 6)

∴ She is paid = 12.50 × 6 = $75

# 2nd part after 4 pm to 6 pm

∵ She is paid $14.25 per hour after 4 pm

∵ She works from 4 pm to 6 pm

- Calculate how many hours between 4 pm and 6 pm

∵ Both times are pm

∴ She works for 2 hours (6 - 4 = 2)

∴ She is paid = 14.25 × 2 = $28.5

- Add the two answers of the 1st part and the 2nd part

∴ She earns = 75 + 28.5 = $103.5

* She earns that day $103.5

7 0
3 years ago
Read 2 more answers
Adult tickets to the fall play cost $6 and student tickets cost $3. The drama class sold 25 more student tickets than adult tick
svlad2 [7]

9514 1404 393

Answer:

  • 90 student tickets
  • 65 adult tickets

Step-by-step explanation:

For many "mixture" problems, it is convenient to use a variable for the quantity of the highest contributor. Here, we can use 'a' to represent the number of adult tickets, because adult tickets cost the most. Then the number of student tickets is (a+25), and the total revenue is ...

  6a +3(a+25) = 660

  9a +75 = 660

  9a = 585

  a = 65

  (a+25) = 90

The drama class sold 90 student tickets and 65 adult tickets.

6 0
3 years ago
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