Answer:
5 weeks
Step-by-step explanation:
We know that she works at a rate of $12 an hour, she also works 20 hours a week.
The total amount she makes per week is $240 (12 x 20). However, that is without deductions. We have to subtract $34 from the $240.
$240 - $34 = $206.
$206 is the amount she makes in a week and she wants to save $950. How many weeks does she have to save? Well, let's divide.
$950 / $206 = 4.6 weeks. However, if we have to round up to 5 weeks.
So, first, what are the two sides?
let's call then x and y
we know that 2(x+y)=12.5 (that's the distance around)
so that means that x+y=6.25 (I just divided both by 2)
now, x=4y (from "4 times as long as it is wide")
so we can substitute:
x+4x=6.25
5x=6.25
x=1.25
so one side, is 1.25 and the other will be 1.25*4=5
and for the area we multiply the two:
1.25*5=6.25 square kilometers, and this is the answer!
Let me express the equation clearly:
lim x→-9 (x²-81)/(x+9)
Initially, we solve this by substituting x=-9 to the equation.
((-9)²-81)/(-9+9) = 0/0
The term 0/0 is undefined. This means that the solution is not see on the number line because it is imaginary. Other undefined terms are N/0 (where N is any number), 0⁰, 0×∞, ∞-∞, 1^∞ and ∞/∞. One way to solve this is by applying L'Hopitals Rule. This can be done by differentiating the numerator and denominator of the fraction independently. Then, you can already substitute the x=-9.
(2x-0)/(1+0) = 2x = 2(-9) = -18
The other easy way is to substitute x=-8.999 to the original equation. Note that the term x→-9 means that x only approaches to -9. Thus, you substitute a number that is very close to -9. Substituting x=-8.999
((-8.999)²-81)/(-8.999+9) = -18
Answer:
(1,2)
Step-by-step explanation:
we know that
The rule of the transformation is equal to
(x, y) ------> (x + 3, y + 1)
Pre-image -----> Image
(x, y) ------> (4, 3)
so
x+3=4 ----> x=4-3=1
y+1=3 ---> y=3-1=2
therefore
The pre-image is the point (1,2)
It would be B (530.7) because if you do 3.14 x 13 x 13 (Or to the second power) Then you get 530.66, the round to the nearest tenths
