Question

How many moles of sulfate ions (SO42−) are present in 1.5 mol of Al2(SO4)3?

Answer 1

1.5 mol* 3 = 4.5 mol

There is 4.5 mol of SO42- in 1.5 mol of Al2(SO4)3~

Answer 2

Answer:4.5 moles of sulfate ions are present in 1.5 moles of $Al_2(SO_4)_3$.

Explanation:

$Al_2(SO_4)_3\rightarrow 2Al^{3+}+3SO_{4}^{2-}$

1 mol of $Al_2(SO_4)_3$ gives 3 moles of sulfate ions.

Moles of sulfate ion in 1.5 moles : $1.5\times 3=4.5 moles$

4.5 moles of sulfate ions are present in 1.5 moles of $Al_2(SO_4)_3$.