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tia_tia [17]
3 years ago
7

How many moles of sulfate ions (SO42−) are present in 1.5 mol of Al2(SO4)3?

Chemistry
2 answers:
asambeis [7]3 years ago
6 0
1.5 mol* 3 = 4.5 mol

There is 4.5 mol of SO42- in 1.5 mol of Al2(SO4)3~
tester [92]3 years ago
3 0

Answer:4.5 moles of sulfate ions are present in 1.5 moles of Al_2(SO_4)_3.

Explanation:

Al_2(SO_4)_3\rightarrow 2Al^{3+}+3SO_{4}^{2-}

1 mol of Al_2(SO_4)_3 gives 3 moles of sulfate ions.

Moles of sulfate ion in 1.5 moles : 1.5\times 3=4.5 moles

4.5 moles of sulfate ions are present in 1.5 moles of Al_2(SO_4)_3.

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