Answer:
<h2>775.75 moles</h2>
Explanation:
To find the number of moles in a substance given it's number of entities we use the formula
where n is the number of moles
N is the number of entities
L is the Avogadro's constant which is
6.02 × 10²³ entities
From the question we have
We have the final answer as
<h3>775.75 moles</h3>
Hope this helps you
C2H4(g) + 2O2(g) → 2CO(g) + 2H2O(g) ∆H1 = −758 kJ mol−1 ....1)
2C(s) + 2H2(g) → C2H4(g) ∆H2 = +52 kJ mol−1 ....2)
H2(g) + O2(g) → H2O(g) ∆H3 = −242 kJ mol−1 ....3)
Now, enthalpy of formation of carbon monoxide is given by :
∆H = ∆H1 + ∆H2 - ∆H3
∆H = ( -758 + 52 - ( -242 ) ) kJ mol−1
∆H = −464 kJ mol−1
Therefore, the enthalpy of formation of carbon monoxide is -464 kJ mol−1.
Hence, this is the required solution.
Answer:
94448421.2201
Explanation:
multiply the value in kilometers by the conversion factor '0.62137119223684'.
So, 152000 kilometers = 152000 × 0.62137119223684 = 94448.42122 miles.
Answer:
2KClO3--------->2KCl + 3O2