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Ber [7]
3 years ago
7

If the pressure on gaseous reactant is increased, the rate of reaction is increased because there is an increase in the

Chemistry
1 answer:
mixer [17]3 years ago
8 0

Answer:

collisions between molecules

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1.54x10-1 L / 2.36x 10-45 solve this in scientific notation
brilliants [131]

Answer:

Fish is the best time to go

Explanation:

Chicken nuggets and a salad and some onion rings and a new charger

3 0
3 years ago
Describe five sources of chemical weathering
artcher [175]
Hydration, oxidation, carbonisation, hydrolysis and dissolution are forms of chemical weathering.
8 0
3 years ago
1.) Which kind of bond would be expected from the above below? (1st image)
mote1985 [20]

Image #1 is clearly sharing their electrons to complete an octet, which makes me believe it is a Double Bond.
Image #2 is a duplicate (if my computer is displaying this picture correctly) which if this is the case and my computer isn't the issue I'd say it is a Double Bond. I don't think "above" and "below" make a difference but it may depend on the attachments and where they were originally placed. Either way Image #1 and #2 are Double Bonds.

Image #3 if I recall accurately is where 4 valence electrons must be gained. I'm a bit fuzzy with valence electrons and recommended viewing Crash Course on this if you'd like to perfect your understanding on Valence Electrons, but I recall a similar question and I remember 4 valence electrons for this type of image. Wish I could help more on this. :(

3 0
3 years ago
Read 2 more answers
Cyclopropane, C3H6, is used as a general anesthetic. If a sample of cyclopropane stored in a 2.36-L container at 10.0 atm and 25
alekssr [168]

Explanation:

The given data is as follows.

     V_{1} = 2.36 L,    T_{1} = 25^{o}C = (25 + 273) K = 298 K,

      P_{1} = 10.0 atm,   V_{2} = 7.79 L,

       T_{2} = ?,       P_{2} = 5.56 atm  

And, according to ideal gas equation,  

               \frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Hence, putting the given values into the above formula to calculate the value of final temperature as follows.          

 \frac{10.0 atm \times 2.36 L}{298 K} = \frac{5.56 atm \times 7.79 L}{T_{2}}

            T_{2} = \frac{43.3124}{0.0792} K

                     = 546.87 K

Thus, we can conclude that the final temperature is 546.87 K.

4 0
3 years ago
Which 3 are they?<br><br> (will mark brainliest)
Paraphin [41]

probably condensation and evaporation and freezing.. PROBABLY idk

8 0
3 years ago
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