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Fed [463]
3 years ago
7

Solve for x A)9 B)33 C)45 D)62

Mathematics
1 answer:
sattari [20]3 years ago
3 0

Answer:

A) 9

Step-by-step explanation:

R=7x+17

S=4x-6

Q=180-110=70

  • 4x-6+7x+17+70=180
  • 11x+81=190
  • 11x=180-81
  • 11x=99
  • x=99/11
  • x=9
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According to the 1991 census, there are about 43406932 people in our country who speak Urdu. Which of the following is the close
amm1812

According to the 1991 census, there are about 43406932 people in our country who speak Urdu. Which of the following is the closest approximation of this number?

A 4 lakhs

B 43 lakhs

C 4 crores

D 43 crores

→ <u>C</u><u> </u><u>4 </u><u>crores</u>

Explaination :

2 - Unit place

3-tens place

9- hundred place

6 - thousand place

0- ten thousand place

4 - lakh place

3 - ten lakh place

4 - crore place

hence , closest approximation of this number is 4 crores.

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2 years ago
What is the image of (9,3) after a dilation by a scale factor of 3 centered at the<br> origin?
sergiy2304 [10]

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This only works if the center of dilation is the origin.

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3 years ago
Please help!!! Rachael deposits $1,500 into a retirement fund each year. The fund earns 8.2% annual interest, compounded monthly
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2 years ago
Question: Ned took a test with 25 questions. He lost 4 points for each of the 6 questions he got wrong and earned an additional
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The reason the correctly answered questions do not factor into the answer is because that is not what the question is asking. Correct answers are not even mentioned :)
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3 years ago
Read 2 more answers
Our faucet is broken, and a plumber has been called. The arrival time of the plumber is uniformly distributed between 1pm and 7p
Ymorist [56]

Answer:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

Step-by-step explanation:

Let A the random variable that represent "The arrival time of the plumber ". And we know that the distribution of A is given by:

A\sim Uniform(1 ,7)

And let B the random variable that represent "The time required to fix the broken faucet". And we know the distribution of B, given by:

B\sim Exp(\lambda=\frac{1}{30 min})

Supposing that the two times are independent, find the expected value and the variance of the time at which the plumber completes the project.

So we are interested on the expected value of A+B, like this

E(A +B)

Since the two random variables are assumed independent, then we have this

E(A+B) = E(A)+E(B)

So we can find the individual expected values for each distribution and then we can add it.

For ths uniform distribution the expected value is given by E(X) =\frac{a+b}{2} where X is the random variable, and a,b represent the limits for the distribution. If we apply this for our case we got:

E(A)=\frac{1+7}{2}=4 hours

The expected value for the exponential distirbution is given by :

E(X)= \int_{0}^\infty x \lambda e^{-\lambda x} dx

If we use the substitution y=\lambda x we have this:

E(X)=\frac{1}{\lambda} \int_{0}^\infty y e^{-\lambda y} dy =\frac{1}{\lambda}

Where X represent the random variable and \lambda the parameter. If we apply this formula to our case we got:

E(B) =\frac{1}{\lambda}=\frac{1}{\frac{1}{30}}=30min

We can convert this into hours and we got E(B) =0.5 hours, and then we can find:

E(A+B) = E(A)+E(B)=4+0.5 =4.5 hours

And in order to find the variance for the random variable A+B we can find the individual variances:

Var(A)= \frac{(b-a)^2}{12}=\frac{(7-1)^2}{12}=3 hours^2

Var(B) =\frac{1}{\lambda^2}=\frac{1}{(\frac{1}{30})^2}=900 min^2 x\frac{1hr^2}{3600 min^2}=0.25 hours^2

We have the following property:

Var(X+Y)= Var(X)+Var(Y) +2 Cov(X,Y)

Since we have independnet variable the Cov(A,B)=0, so then:

Var(A+B)= Var(A)+Var(B)=3+0.25 hours^2=3.25 hours^2

3 0
3 years ago
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