X²+3x-21=0
1) we solve this square equation:
x=[-3⁺₋√(9+84)] / 2=(-3⁺₋√93)/2
We have two solutions:
x₁=(-3-√93)/2
x₂=(-3+√93)/2
2) we compute the product of the 2 solutions found.
[(-3-√93)/2][(-3+√93)/2] =(-3-√93)(-3+√93) / 4=
=(9-93)/4=-84/4=-21
Answer: the product of the 2 solutions of this equation is -21
Answer:
hope it's help you
Step-by-step explanation:
negative 10×three-halves
All angles in a triangle add up to 180
180 = 9 + 15 + 2x - 1 + 3x
180 = 24 - 1 + 2x + 3x
180 = 23 + 5x
180 - 23 = 5x
157 = 5x
Divide both sides by 5
X = 31.4 or 157/5
For matrix subtraction, you subtract the corresponding cell of the second matrix from the first. So, looking at the first spot, you have 4 (from the first matrix) - 4 (from the second matrix) = 0 (the first number in the output matrix). Continuing that for the next spot, -4 - -3 = -4 + 3 = -1. Finally, -2 - 5 = -7. This means your answer is [0 -1 -7].
First you make -1 and 3/4 have a common denominator. 1 has a fraction of 1/1 so times four it is 4/4. Then you add on both sides in order to isolate x and you get 3/10x = 7/4.
Then you isolate x by multyiplying the reciprocal of 3/10 on both sides, 10/3.
3/10 and 10/3 cancel out and you get an answer of x = 70/4.
You could then simplify it to get 35/6 by finding a greasted common multiple of 12 and 70 which is 2 and dividing both by 2 to get a simpilier answer.
So the answer is x = 35/6
