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Contact [7]
3 years ago
12

Given m||n, find the value of x. (4x-9)° (3x+29)°​

Mathematics
1 answer:
anzhelika [568]3 years ago
5 0

Answer:

38°

Step-by-step explanation:

4x-9=3x+29 ------- because corresponding angles are equal

x=38°

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Write the slope-intercept form of the equation of the line
Monica [59]

Answer:

y =-5x-17

Step-by-step explanation:

Slode-intercept is

y = mx + c

The first step is to find the slope, that is the m

To do that, use this formula

Y2 - y1

------------

X2- x1

And u will get - 5

Now since u got m, u also actually have y and x, those are the coordinates they gave u. U can choose either one,(-3, - 2) or (-4, 3), cuz they would give u the same answrs

So let's say I chose (-4, 3)

So x = - 4, y = 3

y=mx +c

3= - 5(-4) +c

C = - 17

Therefore your end product will be

y = - 5x - 17

8 0
3 years ago
Which relation is a function? (10 points and Brainliest for a correct answer)
Volgvan
B I’m pretty sure okay bye
7 0
3 years ago
Triangle XYZ is rotated 90° clockwise about the origin.
Vlad [161]

Answer:

(1,3)

Step-by-step explanation:

Rotating clockwise means that you're rotating by a negative angle measure. The rule for rotating -90 degrees is (x,y)->(y,-x). X is (-3,1) so X' should be (1,3) since you negate -3 to get 3 and switch the x and y coordinates.

4 0
4 years ago
Find the solution to the initial value problem
Karo-lina-s [1.5K]

Answer:

y = (11x + 13)e^(-4x-4)

Step-by-step explanation:

Given y'' + 8y' + 16 = 0

The auxiliary equation to the differential equation is:

m² + 8m + 16 = 0

Factorizing this, we have

(m + 4)² = 0

m = -4 twice

The complimentary solution is

y_c = (C1 + C2x)e^(-4x)

Using the initial conditions

y(-1) = 2

2 = (C1 -C2) e^4

C1 - C2 = 2e^(-4).................................(1)

y'(-1) = 3

y'_c = -4(C1 + C2x)e^(-4x) + C2e^(-4x)

3 = -4(C1 - C2)e^4 + C2e^4

-4C1 + 5C2 = 3e^(-4)..............................(2)

Solving (1) and (2) simultaneously, we have

From (1)

C1 = 2e^(-4) + C2

Using this in (2)

-4[2e^(-4) + C2] + 5C2 = 3e^(-4)

C2 = 11e^(-4)

C1 = 2e^(-4) + 11e^(-4)

= 13e^(-4)

The general solution is now

y = [13e^(-4) + 11xe^(-4)]e^(-4x)

= (11x + 13)e^(-4x-4)

3 0
3 years ago
Rodrigo surveyed some students at his school about their favorite professional sports,
Lunna [17]
The answer is 1 in 15
8 0
3 years ago
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